Roboguru

Dua puluh baterai masing-masing dengan data  dan  disusun seperti tampak dalam gambar.   Kutub-kutub sistem baterai P dan Q dihubungkan dengan rangkaian hambatan yang terhubung seperti jembatan Wheatstone ABDC.  Tentukan hambatan dalam total Rdtot!

Pertanyaan

Dua puluh baterai masing-masing dengan data Error converting from MathML to accessible text. dan begin mathsize 14px style r equals 0 comma 4 straight capital omega end style disusun seperti tampak dalam gambar.

 

Kutub-kutub sistem baterai P dan Q dihubungkan dengan rangkaian hambatan yang terhubung seperti jembatan Wheatstone ABDC.  Tentukan hambatan dalam total Rdtot!

Pembahasan Video:

Pembahasan Soal:

Diketahui:

Ditanya: Rdtot

Jawab:

Menghitung hambatan dalam total pada baterai:

table attributes columnalign right center left columnspacing 0px end attributes row cell R d subscript n space end cell equals cell n cross times R d end cell row cell R d subscript 10 end cell equals cell 10 cross times 0 comma 4 end cell row blank equals cell 4 space capital omega end cell end table; karena ada 2 susunan paralel dari 10 baterai maka:

table attributes columnalign right center left columnspacing 0px end attributes row cell fraction numerator 1 over denominator R d subscript t o t a l end subscript end fraction end cell equals cell fraction numerator 1 over denominator R d subscript 10 end fraction plus fraction numerator 1 over denominator R d subscript 10 end fraction end cell row cell fraction numerator 1 over denominator R d subscript t o t a l end subscript end fraction end cell equals cell 1 fourth plus 1 fourth end cell row cell fraction numerator 1 over denominator R d subscript t o t a l end subscript end fraction end cell equals cell 2 over 4 end cell row cell R d subscript t o t a l end subscript end cell equals cell 2 space straight capital omega end cell end table; karena baterai yang disusun paralel

    
Jadi, jawaban yang tepat adalah 2 space straight capital omega.

Pembahasan terverifikasi oleh Roboguru

Dijawab oleh:

N. Puspita

Terakhir diupdate 30 Agustus 2021

Roboguru sudah bisa jawab 91.4% pertanyaan dengan benar

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Pertanyaan yang serupa

Dua puluh baterai masing-masing dengan data  dan  disusun seperti tampak dalam gambar.   Kutub-kutub sistem baterai P dan Q dihubungkan dengan rangkaian hambatan yang terhubung seperti jembatan Whea...

Pembahasan Soal:

Diketahui:

Ditanya: Vtot

Jawab:

Menghitung tegangan total pada baterai:

table attributes columnalign right center left columnspacing 0px end attributes row cell V subscript n end cell equals cell n cross times V end cell row cell V subscript 10 end cell equals cell 10 cross times 6 end cell row blank equals cell 60 space V end cell end table; karena ada 2 susunan paralel dari 10 baterai maka:

V subscript t o t a l end subscript equals 60 space straight V; baterai yang disusun paralel menghasilkan tegangan yang tetap.

    
Jadi, jawaban yang tepat adalah 60 V.

Roboguru

Dua puluh baterai masing-masing dengan data  dan  disusun seperti tampak dalam gambar.   Kutub-kutub sistem baterai P dan Q dihubungkan dengan rangkaian hambatan yang terhubung seperti jembatan Whea...

Pembahasan Soal:

Diketahui:

Ditanya: RAD

Jawab:

Menghitung Hambatan pengganti pada Jembatan Wheatstone:
Cek hasil kali silang: 2 × 1 ≠ 4 × 1,5; sehingga untuk mencari nilai hambatan pengganti maka diperlukan rangkaian hambatan bantu.

Mengubah hambatan RAB/R1, RAC/R2, dan RBC/R5 menjadi Ra, Rb, dan Rc. Besar nilai hambatan Ra, Rb, dan Rc adalah :

table attributes columnalign right center left columnspacing 0px end attributes row cell R subscript a end cell equals cell fraction numerator R subscript 1 times R subscript 2 over denominator R subscript 1 plus R subscript 2 plus R subscript 5 end fraction end cell row blank equals cell fraction numerator begin display style 2 capital omega times 4 capital omega end style over denominator begin display style 2 capital omega plus 4 capital omega plus 2 capital omega end style end fraction end cell row blank equals cell fraction numerator begin display style 8 capital omega squared end style over denominator begin display style 8 capital omega end style end fraction end cell row blank equals cell 1 capital omega end cell end table

table attributes columnalign right center left columnspacing 0px end attributes row cell R subscript b end cell equals cell fraction numerator R subscript 1 times R subscript 5 over denominator R subscript 1 plus R subscript 2 plus R subscript 5 end fraction end cell row blank equals cell fraction numerator begin display style 2 capital omega times 2 capital omega end style over denominator begin display style 2 capital omega plus 4 capital omega plus 2 capital omega end style end fraction end cell row blank equals cell fraction numerator begin display style 4 capital omega squared end style over denominator begin display style 8 capital omega end style end fraction end cell row blank equals cell 0 comma 5 capital omega end cell end table

table attributes columnalign right center left columnspacing 0px end attributes row cell R subscript c end cell equals cell fraction numerator R subscript 2 times R subscript 5 over denominator R subscript 1 plus R subscript 2 plus R subscript 5 end fraction end cell row blank equals cell fraction numerator begin display style 4 capital omega times 2 capital omega end style over denominator begin display style 2 capital omega plus 4 capital omega plus 2 capital omega end style end fraction end cell row blank equals cell fraction numerator begin display style 8 capital omega squared end style over denominator begin display style 8 capital omega end style end fraction end cell row blank equals cell 1 capital omega end cell end table

Rangkaian jembatan Wheatstone yang baru adalah sebagai berikut :

Menghitung nilai hambatan pengganti :

Rangkaian seri Rb dan R4 :

table attributes columnalign right center left columnspacing 0px end attributes row cell R subscript b comma 4 end subscript end cell equals cell R subscript b plus R subscript 4 end cell row blank equals cell 0 comma 5 space capital omega space plus 1 comma 5 space capital omega space end cell row blank equals cell 2 space capital omega end cell end table

Rangkaian seri Rc dan R3 :

table attributes columnalign right center left columnspacing 0px end attributes row cell R subscript c comma 3 end subscript end cell equals cell R subscript c plus R subscript 3 end cell row blank equals cell 1 space capital omega space plus 1 space capital omega space end cell row blank equals cell 2 space capital omega end cell end table

Rangkaian Paralel :

table attributes columnalign right center left columnspacing 0px end attributes row cell 1 over R subscript p end cell equals cell 1 over R subscript b comma 4 end subscript plus 1 over R subscript c comma 3 end subscript end cell row cell 1 over R subscript p end cell equals cell fraction numerator 1 over denominator 2 straight capital omega end fraction plus fraction numerator 1 over denominator 2 straight capital omega end fraction end cell row cell R subscript P end cell equals cell 1 straight capital omega end cell end table

Besar Hambatan Pengganti :

table attributes columnalign right center left columnspacing 0px end attributes row cell R subscript p e n g g a n t i end subscript end cell equals cell R subscript a plus R subscript P end cell row blank equals cell 1 straight capital omega plus 1 straight capital omega end cell row blank equals cell 2 straight capital omega end cell end table

    
Jadi, jawaban yang tepat adalah 2 capital omega.

Roboguru

Dua puluh baterai masing-masing dengan data  dan  disusun seperti tampak dalam gambar.   Kutub-kutub sistem baterai P dan Q dihubungkan dengan rangkaian hambatan yang terhubung seperti jembatan Whea...

Pembahasan Soal:

Diketahui:

Ditanya: I

Jawab:

Menghitung tegangan total pada baterai:

table attributes columnalign right center left columnspacing 0px end attributes row cell V subscript n end cell equals cell n cross times V end cell row cell V subscript 10 end cell equals cell 10 cross times 6 end cell row blank equals cell 60 space V end cell end table; karena ada 2 susunan paralel dari 10 baterai maka:

V subscript t o t a l end subscript equals 60 space straight V; baterai yang disusun paralel menghasilkan tegangan yang tetap.

Menghitung hambatan dalam total pada baterai:

table attributes columnalign right center left columnspacing 0px end attributes row cell R d subscript n space end cell equals cell n cross times R d end cell row cell R d subscript 10 end cell equals cell 10 cross times 0 comma 4 end cell row blank equals cell 4 space capital omega end cell end table; karena ada 2 susunan paralel dari 10 baterai maka:

table attributes columnalign right center left columnspacing 0px end attributes row cell fraction numerator 1 over denominator R d subscript t o t a l end subscript end fraction end cell equals cell fraction numerator 1 over denominator R d subscript 10 end fraction plus fraction numerator 1 over denominator R d subscript 10 end fraction end cell row cell fraction numerator 1 over denominator R d subscript t o t a l end subscript end fraction end cell equals cell 1 fourth plus 1 fourth end cell row cell fraction numerator 1 over denominator R d subscript t o t a l end subscript end fraction end cell equals cell 2 over 4 end cell row cell R d subscript t o t a l end subscript end cell equals cell 2 space straight capital omega end cell end table; karena baterai yang disusun paralel

Menghitung Hambatan pengganti pada Jembatan Wheatstone:
Cek hasil kali silang: 2 × 1 ≠ 4 × 1,5; sehingga untuk mencari nilai hambatan pengganti maka diperlukan rangkaian hambatan bantu.

Mengubah hambatan RAB/R1, RAC/R2, dan RBC/R5 menjadi Ra, Rb, dan Rc. Besar nilai hambatan Ra, Rb, dan Rc adalah :

table attributes columnalign right center left columnspacing 0px end attributes row cell R subscript a end cell equals cell fraction numerator R subscript 1 times R subscript 2 over denominator R subscript 1 plus R subscript 2 plus R subscript 5 end fraction end cell row blank equals cell fraction numerator begin display style 2 capital omega times 4 capital omega end style over denominator begin display style 2 capital omega plus 4 capital omega plus 2 capital omega end style end fraction end cell row blank equals cell fraction numerator begin display style 8 capital omega squared end style over denominator begin display style 8 capital omega end style end fraction end cell row blank equals cell 1 capital omega end cell end table

table attributes columnalign right center left columnspacing 0px end attributes row cell R subscript b end cell equals cell fraction numerator R subscript 1 times R subscript 5 over denominator R subscript 1 plus R subscript 2 plus R subscript 5 end fraction end cell row blank equals cell fraction numerator begin display style 2 capital omega times 2 capital omega end style over denominator begin display style 2 capital omega plus 4 capital omega plus 2 capital omega end style end fraction end cell row blank equals cell fraction numerator begin display style 4 capital omega squared end style over denominator begin display style 8 capital omega end style end fraction end cell row blank equals cell 0 comma 5 capital omega end cell end table

table attributes columnalign right center left columnspacing 0px end attributes row cell R subscript c end cell equals cell fraction numerator R subscript 2 times R subscript 5 over denominator R subscript 1 plus R subscript 2 plus R subscript 5 end fraction end cell row blank equals cell fraction numerator begin display style 4 capital omega times 2 capital omega end style over denominator begin display style 2 capital omega plus 4 capital omega plus 2 capital omega end style end fraction end cell row blank equals cell fraction numerator begin display style 8 capital omega squared end style over denominator begin display style 8 capital omega end style end fraction end cell row blank equals cell 1 capital omega end cell end table

Rangkaian jembatan Wheatstone yang baru adalah sebagai berikut :

Menghitung nilai hambatan pengganti :

Rangkaian seri Rb dan R4 :

table attributes columnalign right center left columnspacing 0px end attributes row cell R subscript b comma 4 end subscript end cell equals cell R subscript b plus R subscript 4 end cell row blank equals cell 0 comma 5 space capital omega space plus 1 comma 5 space capital omega space end cell row blank equals cell 2 space capital omega end cell end table

Rangkaian seri Rc dan R3 :

table attributes columnalign right center left columnspacing 0px end attributes row cell R subscript c comma 3 end subscript end cell equals cell R subscript c plus R subscript 3 end cell row blank equals cell 1 space capital omega space plus 1 space capital omega space end cell row blank equals cell 2 space capital omega end cell end table

Rangkaian Paralel :

table attributes columnalign right center left columnspacing 0px end attributes row cell 1 over R subscript p end cell equals cell 1 over R subscript b comma 4 end subscript plus 1 over R subscript c comma 3 end subscript end cell row cell 1 over R subscript p end cell equals cell fraction numerator 1 over denominator 2 straight capital omega end fraction plus fraction numerator 1 over denominator 2 straight capital omega end fraction end cell row cell R subscript P end cell equals cell 1 straight capital omega end cell end table

Besar Hambatan Pengganti :

table attributes columnalign right center left columnspacing 0px end attributes row cell R subscript p e n g g a n t i end subscript end cell equals cell R subscript a plus R subscript P end cell row blank equals cell 1 straight capital omega plus 1 straight capital omega end cell row blank equals cell 2 straight capital omega end cell end table

Menghitung kuat arus :

table attributes columnalign right center left columnspacing 0px end attributes row I equals cell V subscript t o t end subscript over R subscript t o t end subscript end cell row blank equals cell fraction numerator V subscript t o t end subscript over denominator R subscript d plus R subscript p e n g g a n t i end subscript end fraction end cell row blank equals cell fraction numerator 60 space straight V over denominator 2 straight capital omega plus 2 straight capital omega end fraction end cell row blank equals cell fraction numerator 60 space straight V over denominator 4 straight capital omega end fraction end cell row blank equals cell 15 space straight A end cell end table
    
Jadi, jawaban yang tepat adalah 15 A.

Roboguru

Dua puluh baterai masing-masing dengan data  dan  disusun seperti tampak dalam gambar.   Kutub-kutub sistem baterai P dan Q dihubungkan dengan rangkaian hambatan yang terhubung seperti jembatan Whea...

Pembahasan Soal:

Diketahui:

Ditanya: VPQ

Jawab:

Menghitung tegangan total pada baterai:

table attributes columnalign right center left columnspacing 0px end attributes row cell V subscript n end cell equals cell n cross times V end cell row cell V subscript 10 end cell equals cell 10 cross times 6 end cell row blank equals cell 60 space V end cell end table; karena ada 2 susunan paralel dari 10 baterai maka:

V subscript t o t a l end subscript equals 60 space straight V; baterai yang disusun paralel menghasilkan tegangan yang tetap.

Menghitung hambatan dalam total pada baterai:

table attributes columnalign right center left columnspacing 0px end attributes row cell R d subscript n space end cell equals cell n cross times R d end cell row cell R d subscript 10 end cell equals cell 10 cross times 0 comma 4 end cell row blank equals cell 4 space capital omega end cell end table; karena ada 2 susunan paralel dari 10 baterai maka:

table attributes columnalign right center left columnspacing 0px end attributes row cell fraction numerator 1 over denominator R d subscript t o t a l end subscript end fraction end cell equals cell fraction numerator 1 over denominator R d subscript 10 end fraction plus fraction numerator 1 over denominator R d subscript 10 end fraction end cell row cell fraction numerator 1 over denominator R d subscript t o t a l end subscript end fraction end cell equals cell 1 fourth plus 1 fourth end cell row cell fraction numerator 1 over denominator R d subscript t o t a l end subscript end fraction end cell equals cell 2 over 4 end cell row cell R d subscript t o t a l end subscript end cell equals cell 2 space straight capital omega end cell end table; karena baterai yang disusun paralel

Menghitung Hambatan pengganti pada Jembatan Wheatstone:
Cek hasil kali silang: 2 × 1 ≠ 4 × 1,5; sehingga untuk mencari nilai hambatan pengganti maka diperlukan rangkaian hambatan bantu.

Mengubah hambatan RAB/R1, RAC/R2, dan RBC/R5 menjadi Ra, Rb, dan Rc. Besar nilai hambatan Ra, Rb, dan Rc adalah :

table attributes columnalign right center left columnspacing 0px end attributes row cell R subscript a end cell equals cell fraction numerator R subscript 1 times R subscript 2 over denominator R subscript 1 plus R subscript 2 plus R subscript 5 end fraction end cell row blank equals cell fraction numerator begin display style 2 capital omega times 4 capital omega end style over denominator begin display style 2 capital omega plus 4 capital omega plus 2 capital omega end style end fraction end cell row blank equals cell fraction numerator begin display style 8 capital omega squared end style over denominator begin display style 8 capital omega end style end fraction end cell row blank equals cell 1 capital omega end cell end table

table attributes columnalign right center left columnspacing 0px end attributes row cell R subscript b end cell equals cell fraction numerator R subscript 1 times R subscript 5 over denominator R subscript 1 plus R subscript 2 plus R subscript 5 end fraction end cell row blank equals cell fraction numerator begin display style 2 capital omega times 2 capital omega end style over denominator begin display style 2 capital omega plus 4 capital omega plus 2 capital omega end style end fraction end cell row blank equals cell fraction numerator begin display style 4 capital omega squared end style over denominator begin display style 8 capital omega end style end fraction end cell row blank equals cell 0 comma 5 capital omega end cell end table

table attributes columnalign right center left columnspacing 0px end attributes row cell R subscript c end cell equals cell fraction numerator R subscript 2 times R subscript 5 over denominator R subscript 1 plus R subscript 2 plus R subscript 5 end fraction end cell row blank equals cell fraction numerator begin display style 4 capital omega times 2 capital omega end style over denominator begin display style 2 capital omega plus 4 capital omega plus 2 capital omega end style end fraction end cell row blank equals cell fraction numerator begin display style 8 capital omega squared end style over denominator begin display style 8 capital omega end style end fraction end cell row blank equals cell 1 capital omega end cell end table

Rangkaian jembatan Wheatstone yang baru adalah sebagai berikut :

Menghitung nilai hambatan pengganti :

Rangkaian seri Rb dan R4 :

table attributes columnalign right center left columnspacing 0px end attributes row cell R subscript b comma 4 end subscript end cell equals cell R subscript b plus R subscript 4 end cell row blank equals cell 0 comma 5 space capital omega space plus 1 comma 5 space capital omega space end cell row blank equals cell 2 space capital omega end cell end table

Rangkaian seri Rc dan R3 :

table attributes columnalign right center left columnspacing 0px end attributes row cell R subscript c comma 3 end subscript end cell equals cell R subscript c plus R subscript 3 end cell row blank equals cell 1 space capital omega space plus 1 space capital omega space end cell row blank equals cell 2 space capital omega end cell end table

Rangkaian Paralel :

table attributes columnalign right center left columnspacing 0px end attributes row cell 1 over R subscript p end cell equals cell 1 over R subscript b comma 4 end subscript plus 1 over R subscript c comma 3 end subscript end cell row cell 1 over R subscript p end cell equals cell fraction numerator 1 over denominator 2 straight capital omega end fraction plus fraction numerator 1 over denominator 2 straight capital omega end fraction end cell row cell R subscript P end cell equals cell 1 straight capital omega end cell end table

Besar Hambatan Pengganti :

table attributes columnalign right center left columnspacing 0px end attributes row cell R subscript p e n g g a n t i end subscript end cell equals cell R subscript a plus R subscript P end cell row blank equals cell 1 straight capital omega plus 1 straight capital omega end cell row blank equals cell 2 straight capital omega end cell end table

Menghitung kuat arus :

table attributes columnalign right center left columnspacing 0px end attributes row I equals cell V subscript t o t end subscript over R subscript t o t end subscript end cell row blank equals cell fraction numerator V subscript t o t end subscript over denominator R subscript d plus R subscript p e n g g a n t i end subscript end fraction end cell row blank equals cell fraction numerator 60 space straight V over denominator 2 straight capital omega plus 2 straight capital omega end fraction end cell row blank equals cell fraction numerator 60 space straight V over denominator 4 straight capital omega end fraction end cell row blank equals cell 15 space straight A end cell end table

Menghitung tegangan jepit VPQ

table attributes columnalign right center left columnspacing 0px end attributes row cell V subscript P Q end subscript end cell equals cell I times R subscript P Q end subscript end cell row blank equals cell 15 times 2 end cell row blank equals cell 30 space straight V end cell end table
    
Jadi, jawaban yang tepat adalah 30 V.

Roboguru

Sebuah sumber tegangan ideal dengan GGL 14,8 volt dihubungkan pada titik P dan Q.   Hitunglah hambatan pengganti RPQ!

Pembahasan Soal:

Diketahui:

epsilon equals space 14 comma 8 space straight V R subscript 1 equals 4 space straight capital omega straight R subscript 2 equals 8 space straight capital omega straight R subscript 3 equals 2 space straight capital omega straight R subscript 4 equals 6 space straight capital omega straight R subscript 5 equals straight R subscript AB equals 2 space straight capital omega 

Ditanya: RPQ dan VAB

Jawab:

Menghitung hambatan pengganti RPQ

Cek hasil kali silang :
table attributes columnalign right center left columnspacing 0px end attributes row cell R subscript 1 cross times R subscript 3 end cell not equal to cell R subscript 2 cross times R subscript 4 end cell row cell 4 cross times 2 end cell not equal to cell 8 cross times 6 end cell end table

Untuk menghitung nilai hambatan pengganti, diperlukan rangkaian hambatan bantu seperti pada gambar berikut :

Besar nilai hambatan Ra, Rb, dan Rc dapat dicari menggunakan rumus berikut :

table attributes columnalign right center left columnspacing 0px end attributes row cell R subscript a end cell equals cell fraction numerator R subscript 1 times R subscript 2 over denominator R subscript 1 plus R subscript 2 plus R subscript 5 end fraction end cell row blank equals cell fraction numerator begin display style 4 capital omega times 8 capital omega end style over denominator begin display style 4 capital omega plus 8 capital omega plus 2 capital omega end style end fraction end cell row blank equals cell fraction numerator begin display style 32 capital omega squared end style over denominator begin display style 14 capital omega end style end fraction end cell row blank equals cell 2 comma 3 capital omega end cell end table

table attributes columnalign right center left columnspacing 0px end attributes row cell R subscript b end cell equals cell fraction numerator R subscript 1 times R subscript 5 over denominator R subscript 1 plus R subscript 2 plus R subscript 5 end fraction end cell row blank equals cell fraction numerator begin display style 4 capital omega times 2 capital omega end style over denominator begin display style 4 capital omega plus 8 capital omega plus 2 capital omega end style end fraction end cell row blank equals cell fraction numerator begin display style 8 capital omega squared end style over denominator begin display style 14 capital omega end style end fraction end cell row blank equals cell 0 comma 6 space capital omega end cell end table

table attributes columnalign right center left columnspacing 0px end attributes row cell R subscript c end cell equals cell fraction numerator R subscript 2 times R subscript 5 over denominator R subscript 1 plus R subscript 2 plus R subscript 5 end fraction end cell row blank equals cell fraction numerator begin display style 8 capital omega times 2 capital omega end style over denominator begin display style 4 capital omega plus 8 capital omega plus 2 capital omega end style end fraction end cell row blank equals cell fraction numerator begin display style 16 capital omega squared end style over denominator begin display style 14 capital omega end style end fraction end cell row blank equals cell 1 comma 1 space capital omega end cell end table

Rangkaian yang baru adalah sebagai berikut :

Nilai hambatan pengganti dihitung menggunakan rumus pada rangkaian seri dan paralel :

Rangkaian seri Rb dan R4:

table attributes columnalign right center left columnspacing 0px end attributes row cell R subscript b comma 4 end subscript end cell equals cell R subscript b plus R subscript 4 end cell row blank equals cell 0 comma 6 space straight capital omega space plus 6 space straight capital omega space end cell row blank equals cell 6 comma 6 space straight capital omega space end cell end table 

Rangkaian seri Rc dan R3:

table attributes columnalign right center left columnspacing 0px end attributes row cell R subscript c comma 3 end subscript end cell equals cell R subscript c plus R subscript 3 end cell row blank equals cell 1 comma 1 space straight capital omega space plus 2 space straight capital omega space end cell row blank equals cell 3 comma 2 space straight capital omega space end cell end table 

Rangkaian Paralel:

 table attributes columnalign right center left columnspacing 0px end attributes row cell 1 over R subscript p end cell equals cell 1 over R subscript b comma 4 end subscript plus 1 over R subscript c comma 3 end subscript end cell row cell fraction numerator begin display style 1 end style over denominator begin display style R subscript p end style end fraction end cell equals cell fraction numerator begin display style 1 end style over denominator begin display style 6 comma 6 straight capital omega end style end fraction plus fraction numerator begin display style 1 end style over denominator begin display style 3 comma 2 straight capital omega end style end fraction end cell row cell R subscript p end cell equals cell fraction numerator 6 comma 6 straight capital omega times 3 comma 2 straight capital omega over denominator 6 comma 6 straight capital omega plus 3 comma 2 straight capital omega end fraction end cell row blank equals cell fraction numerator 21 comma 12 straight capital omega squared over denominator 9 comma 8 straight capital omega end fraction end cell row blank equals cell 2 space straight capital omega end cell end table 

Besar Hambatan Pengganti :

table attributes columnalign right center left columnspacing 0px end attributes row cell R subscript p e n g g a n t i end subscript end cell equals cell R subscript a plus R subscript p end cell row blank equals cell 2 comma 3 space straight capital omega plus 2 space straight capital omega end cell row blank equals cell 4 comma 3 space straight capital omega end cell end table 

    
Jadi, jawaban yang tepat adalah 4 comma 3 space capital omega.

Roboguru

Roboguru sudah bisa jawab 91.4% pertanyaan dengan benar

Tapi Roboguru masih mau belajar. Menurut kamu pembahasan kali ini sudah membantu, belum?

Membantu

Kurang Membantu

Apakah pembahasan ini membantu?

Belum menemukan yang kamu cari?

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