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Pertanyaan

( 2 m n − 2 ) 3 8 m 5 n 4 ​ disederhanakan menjadi ....

 disederhanakan menjadi 

  1. 4 m squared n to the power of 10

  2. 4 m squared n to the power of 9

  3. m squared n to the power of 10

  4. m squared n to the power of 9

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E. Lestari

Master Teacher

Mahasiswa/Alumni Universitas Sebelas Maret

Jawaban terverifikasi

Jawaban

jawaban yang benar adalah C.

jawaban yang benar adalah C.

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Pembahasan

Diketahui maka berdasarkan sifat bilangan berpangkat maka diperoleh Berdasarkan sifat bilangan berpangkat yaitu maka Berdasarkan sifat bilangan berpangkat yaitu maka Jadi disederhanakan menjadi . Oleh karena itu, jawaban yang benar adalah C.

Diketahui fraction numerator 8 m to the power of 5 n to the power of 4 over denominator open parentheses 2 m n to the power of negative 2 end exponent close parentheses cubed end fraction maka berdasarkan sifat bilangan berpangkat open parentheses a cross times b close parentheses to the power of m equals a to the power of m cross times b to the power of m maka diperoleh

fraction numerator 8 m to the power of 5 n to the power of 4 over denominator open parentheses 2 m n to the power of negative 2 end exponent close parentheses cubed end fraction equals fraction numerator 8 m to the power of 5 n to the power of 4 over denominator 2 cubed m cubed open parentheses n to the power of negative 2 end exponent close parentheses cubed end fraction

Berdasarkan sifat bilangan berpangkat yaitu open parentheses a to the power of m close parentheses to the power of n equals a to the power of m cross times n end exponent maka

table attributes columnalign right center left columnspacing 0px end attributes row cell fraction numerator 8 m to the power of 5 n to the power of 4 over denominator open parentheses 2 m n to the power of negative 2 end exponent close parentheses cubed end fraction end cell equals cell fraction numerator 8 m to the power of 5 n to the power of 4 over denominator 2 cubed m cubed open parentheses n to the power of negative 2 end exponent close parentheses cubed end fraction end cell row blank equals cell fraction numerator up diagonal strike 8 m to the power of 5 n to the power of 4 over denominator up diagonal strike 8 m cubed n to the power of negative 2 cross times 3 end exponent end fraction end cell row blank equals cell fraction numerator m to the power of 5 n to the power of 4 over denominator m cubed n to the power of negative 6 end exponent end fraction end cell end table

Berdasarkan sifat bilangan berpangkat yaitu a to the power of m divided by a to the power of n equals a to the power of m minus n end exponent maka

table attributes columnalign right center left columnspacing 0px end attributes row cell fraction numerator 8 m to the power of 5 n to the power of 4 over denominator open parentheses 2 m n to the power of negative 2 end exponent close parentheses cubed end fraction end cell equals cell fraction numerator 8 m to the power of 5 n to the power of 4 over denominator 2 cubed m cubed open parentheses n to the power of negative 2 end exponent close parentheses cubed end fraction end cell row blank equals cell fraction numerator up diagonal strike 8 m to the power of 5 n to the power of 4 over denominator up diagonal strike 8 m cubed n to the power of negative 2 cross times 3 end exponent end fraction end cell row blank equals cell fraction numerator m to the power of 5 n to the power of 4 over denominator m cubed n to the power of negative 6 end exponent end fraction end cell row blank equals cell m to the power of 5 minus 3 end exponent n to the power of 4 minus open parentheses negative 6 close parentheses end exponent end cell row blank equals cell m squared n to the power of 4 plus 6 end exponent end cell row blank equals cell m squared n to the power of 10 end cell end table

Jadi fraction numerator 8 m to the power of 5 n to the power of 4 over denominator open parentheses 2 m n to the power of negative 2 end exponent close parentheses cubed end fraction disederhanakan menjadi m squared n to the power of 10.

Oleh karena itu, jawaban yang benar adalah C.

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