Pertanyaan

Diketahui K sp AgCl = 1 × 1 0 − 5 ; Ag 2 CrO 4 = 1 , 1 × 1 0 − 12 ; dan Ag 3 AsO 4 = 1 × 1 0 − 22 . Urutkan ketiga garam tersebut berdasarkan kelarutannya, dimulai dari yang terkecil!

Diketahui $K_{sp}$

$AgCl = 1 \times 1 0^{- 5}; Ag_{2} CrO_{4} = 1, 1 \times 1 0^{- 12}; dan Ag_{3} AsO_{4} = 1 \times 1 0^{- 22}$ .
Urutkan ketiga garam tersebut berdasarkan kelarutannya, dimulai dari yang terkecil! $\;$

S. Lubis

Master Teacher

Jawaban terverifikasi

Pembahasan

Menentukan Kelarutan Menentukan Kelarutan Menentukan Kelarutan Maka dapat diurutkan dimulai dari yang kelarutannya terkecil yaitu sebagi berikut: .

Menentukan Kelarutan Ag Cl

Menentukan Kelarutan Ag subscript bold 2 Cr O subscript bold 4

$table attributes columnalign right center left columnspacing 0px end attributes row cell Ag subscript 2 Cr O subscript 4 open parentheses italic s close parentheses end cell rightwards harpoon over leftwards harpoon cell 2 Ag to the power of plus sign left parenthesis italic a italic q right parenthesis plus Cr O subscript 4 to the power of 2 minus sign end exponent left parenthesis italic a italic q right parenthesis end cell row blank blank cell space italic space italic space italic space italic space italic space italic space italic space italic s italic space italic space italic space italic space italic space italic space italic space italic space italic space italic space italic space italic space italic space italic space 2 italic s italic space italic space italic space italic space italic space italic space italic space italic space italic space italic space italic space italic space italic space italic s end cell row blank blank blank row cell K subscript sp space Ag subscript 2 Cr O subscript 4 end cell equals cell open square brackets Ag to the power of plus sign close square brackets squared open square brackets Cr O subscript 4 to the power of 2 minus sign end exponent close square brackets end cell row cell K subscript sp space Ag subscript 2 Cr O subscript 4 end cell equals cell open square brackets italic 2 italic s close square brackets squared open square brackets italic s close square brackets end cell row cell K subscript sp space Ag subscript 2 Cr O subscript 4 end cell equals cell 4 italic s cubed end cell row italic s equals cell cube root of K subscript sp over 4 end root end cell row italic s equals cell cube root of fraction numerator 1 comma 1 cross times 10 to the power of negative sign 12 end exponent over denominator 4 end fraction end root end cell row cell italic s bold italic space Ag subscript bold 2 Cr O subscript bold 4 end cell bold equals cell bold 1 bold comma bold 4 bold cross times bold 10 to the power of bold minus sign bold 4 end exponent bold space bold mol bold space italic L to the power of bold minus sign bold 1 end exponent end cell end table$

Menentukan Kelarutan Ag subscript bold 3 As O subscript bold 4

$table attributes columnalign right center left columnspacing 0px end attributes row cell Ag subscript 3 As O subscript 4 open parentheses italic s close parentheses end cell rightwards harpoon over leftwards harpoon cell 3 Ag to the power of plus sign left parenthesis italic a italic q right parenthesis plus As O subscript 4 to the power of 3 minus sign end exponent left parenthesis italic a italic q right parenthesis end cell row blank blank cell space italic space italic space italic space italic space italic space italic space italic space italic s italic space italic space italic space italic space italic space italic space italic space italic space italic space italic space italic space italic space italic space italic space italic 3 italic s italic space italic space italic space italic space italic space italic space italic space italic space italic space italic space italic space italic space italic space italic space italic space italic space italic s end cell row blank blank blank row cell K subscript sp space Ag subscript 3 As O subscript 4 end cell equals cell open square brackets Ag to the power of plus sign close square brackets cubed open square brackets As O subscript 4 to the power of 3 minus sign end exponent close square brackets end cell row cell K subscript sp space Ag subscript 3 As O subscript 4 end cell equals cell open square brackets italic 3 italic s close square brackets cubed open square brackets italic s close square brackets end cell row cell K subscript sp space Ag subscript 3 As O subscript 4 end cell equals cell 27 italic s to the power of 4 end cell row italic s equals cell fourth root of K subscript sp over 27 end root end cell row italic s equals cell fourth root of fraction numerator 1 cross times 10 to the power of negative sign 22 end exponent over denominator 27 end fraction end root end cell row cell italic s bold italic space Ag subscript bold 3 As O subscript bold 4 end cell bold equals cell bold 1 bold comma bold 39 bold cross times bold 10 to the power of bold minus sign bold 6 end exponent bold space bold mol bold space italic L to the power of bold minus sign bold 1 end exponent end cell end table$

Maka dapat diurutkan dimulai dari yang kelarutannya terkecil yaitu sebagi berikut:

Ag subscript bold 3 S O subscript bold 4 bold less than Ag subscript bold 2 Cr O subscript bold 4 bold less than Ag Cl . space

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