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Diketahui: A subscript r colon space C equals 12 space g space mol to the power of negative sign 1 end exponent comma space N equals 14 space g space mol to the power of negative sign 1 end exponent comma space O equals 16 space g space mol to the power of negative sign 1 end exponent comma space S equals 32 space g space mol to the power of negative sign 1 end exponent comma space H equals 1 space g space mol to the power of negative sign 1 end exponent comma space Fe equals 56 space g space mol to the power of negative sign 1 end exponent

Tentukan massa dari 4,48 liter gas dinitrogen pentaoksida (STP)!space 

I. Solichah

Master Teacher

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Jawaban

massa N subscript bold 2 O subscript bold 5 adalah 21,6 gram.space 

Pembahasan

Menentukan mol N subscript bold 2 O subscript bold 5

table attributes columnalign right center left columnspacing 0px end attributes row cell mol space N subscript 2 O subscript 5 end cell equals cell fraction numerator V space N subscript 2 O subscript 5 over denominator V subscript STP end fraction end cell row cell mol space N subscript 2 O subscript 5 end cell equals cell fraction numerator 4 comma 48 space L over denominator 22 comma 4 space L end fraction end cell row cell mol space N subscript 2 O subscript 5 end cell equals cell 0 comma 2 space mol end cell row blank blank blank end table 
 

Menentukan massa N subscript bold 2 O subscript bold 5 

mol space N subscript 2 O subscript 5 equals fraction numerator italic g space N subscript 2 O subscript 5 over denominator M subscript r space N subscript 2 O subscript 5 end fraction italic g space N subscript 2 O subscript 5 double bond mol space N subscript 2 O subscript 5 cross times M subscript r space N subscript 2 O subscript 5 italic g space N subscript 2 O subscript 5 double bond mol space N subscript 2 O subscript 5 cross times left curly bracket left parenthesis 2 cross times A subscript r space N right parenthesis plus left parenthesis 5 cross times A subscript r space O right parenthesis right curly bracket italic g space N subscript 2 O subscript 5 equals 0 comma 2 space mol cross times left curly bracket left parenthesis 2 cross times 14 space g space mol to the power of negative sign 1 end exponent right parenthesis plus left parenthesis 5 cross times 16 space g space mol to the power of negative sign 1 end exponent right parenthesis right curly bracket italic g space N subscript 2 O subscript 5 equals 21 comma 6 space g 

Jadi massa N subscript bold 2 O subscript bold 5 adalah 21,6 gram.space 

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