Pertanyaan

Diketahui: A r : C = 12 g mol − 1 , N = 14 g mol − 1 , O = 16 g mol − 1 , S = 32 g mol − 1 , H = 1 g mol − 1 , Fe = 56 g mol − 1 Tentukan massa dari 4,48 liter gas dinitrogen pentaoksida (STP)!

Diketahui: $A_{r} : C = 12 g mol^{- 1}, N = 14 g mol^{- 1}, O = 16 g mol^{- 1}, S = 32 g mol^{- 1}, H = 1 g mol^{- 1}, Fe = 56 g mol^{- 1}$

Tentukan massa dari 4,48 liter gas dinitrogen pentaoksida (STP)! $\;$

I. Solichah

Master Teacher

Jawaban terverifikasi

Jawaban

massa adalah 21,6 gram.

massa

adalah 21,6 gram.

Pembahasan

Menentukan mol Menentukan massa Jadi massa adalah 21,6 gram.

Menentukan mol N subscript bold 2 O subscript bold 5

$table attributes columnalign right center left columnspacing 0px end attributes row cell mol space N subscript 2 O subscript 5 end cell equals cell fraction numerator V space N subscript 2 O subscript 5 over denominator V subscript STP end fraction end cell row cell mol space N subscript 2 O subscript 5 end cell equals cell fraction numerator 4 comma 48 space L over denominator 22 comma 4 space L end fraction end cell row cell mol space N subscript 2 O subscript 5 end cell equals cell 0 comma 2 space mol end cell row blank blank blank end table$

Menentukan massa N subscript bold 2 O subscript bold 5

$mol space N subscript 2 O subscript 5 equals fraction numerator italic g space N subscript 2 O subscript 5 over denominator M subscript r space N subscript 2 O subscript 5 end fraction italic g space N subscript 2 O subscript 5 double bond mol space N subscript 2 O subscript 5 cross times M subscript r space N subscript 2 O subscript 5 italic g space N subscript 2 O subscript 5 double bond mol space N subscript 2 O subscript 5 cross times left curly bracket left parenthesis 2 cross times A subscript r space N right parenthesis plus left parenthesis 5 cross times A subscript r space O right parenthesis right curly bracket italic g space N subscript 2 O subscript 5 equals 0 comma 2 space mol cross times left curly bracket left parenthesis 2 cross times 14 space g space mol to the power of negative sign 1 end exponent right parenthesis plus left parenthesis 5 cross times 16 space g space mol to the power of negative sign 1 end exponent right parenthesis right curly bracket italic g space N subscript 2 O subscript 5 equals 21 comma 6 space g$

Jadi massa N subscript bold 2 O subscript bold 5 adalah 21,6 gram.