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Diketahui segitiga PQR siku – siku di Q dan sin R = 17 8 (P dan R sudut lancip). Nilai dari ( 1 − cos R ) ( 1 + sin P ) adalah...

Diketahui segitiga PQR siku – siku di Q dan $sin R = \frac{8}{17}$ (P dan R sudut lancip). Nilai dari $(1 - cos R) (1 + sin P)$ adalah...

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I. Sutiawan

Master Teacher

Mahasiswa/Alumni Universitas Pasundan

Jawaban terverifikasi

Pembahasan

$sin space straight R equals 8 over 17 cos space straight R equals fraction numerator square root of 17 squared minus 8 squared end root over denominator 17 end fraction equals 15 over 17 sin space straight P equals 15 over 17 cos space straight P equals 8 over 17 open parentheses 1 minus space cos space straight R close parentheses open parentheses 1 plus sin space straight P close parentheses equals 1 plus sin space straight P minus cos space straight R minus in space straight P space cos space straight R space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space equals 1 plus 15 over 17 minus 15 over 17 minus 15 over 17 times 15 over 17 space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space equals 1 minus 225 over 289 space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space equals 64 over 289$