Iklan

Pertanyaan

Diketahui pH larutan basa lemah (LOH) dengan konsentrasi 0,1 M sebesar 11+ log 4. Tentukan pH larutan yang terjadi jikake dalam 100 mL larutan LOH 0,1 M dimasukkan 100 mL larutan HI 0,1 M!

Diketahui pH larutan basa lemah (LOH) dengan konsentrasi 0,1 M sebesar 11 + log 4. Tentukan pH larutan yang terjadi jika ke dalam 100 mL larutan LOH 0,1 M dimasukkan 100 mL larutan HI 0,1 M!

Ikuti Tryout SNBT & Menangkan E-Wallet 100rb

Habis dalam

00

:

05

:

08

:

27

Klaim

Iklan

Y. Rochmawatie

Master Teacher

Jawaban terverifikasi

Jawaban

pH larutan adalah 6 - log 1,77

pH larutan adalah 6 - log 1,77

Pembahasan

Pembahasan
lock

Menentukan Kb larutan basa lemah Menentukan pH larutan garam Jadi, pH larutan adalah 6 - log 1,77

Menentukan Kb larutan basa lemah

begin mathsize 14px style pH space LOH equals 11 plus log space 4 pOH equals 14 minus sign open parentheses 11 plus log space 4 close parentheses pOH equals 3 minus sign log 4 open square brackets O H to the power of minus sign close square brackets equals 4 space cross times space 10 to the power of negative sign 3 end exponent open square brackets O H to the power of minus sign close square brackets equals square root of K subscript b space cross times space M end root 4 space cross times space 10 to the power of negative sign 3 end exponent equals square root of K subscript b space cross times space 10 to the power of negative sign 1 end exponent end root 16 space cross times space 10 to the power of negative sign 6 end exponent equals K subscript b space cross times space 10 to the power of negative sign 1 end exponent K subscript b equals 1 comma 6 space cross times space 10 to the power of negative sign 4 end exponent end style 

Menentukan pH larutan garam

begin mathsize 14px style open square brackets H to the power of plus sign close square brackets equals square root of K subscript w over K subscript b space cross times space M end root open square brackets H to the power of plus sign close square brackets equals square root of fraction numerator 10 to the power of negative sign 14 end exponent over denominator 1 comma 6 space cross times space 10 to the power of negative sign 4 end exponent end fraction space cross times space 10 over 200 end root open square brackets H to the power of plus sign close square brackets equals square root of fraction numerator 10 to the power of negative sign 14 end exponent over denominator 1 comma 6 space cross times space 10 to the power of negative sign 4 end exponent end fraction space cross times space 5 space cross times space 10 to the power of negative sign 2 end exponent end root open square brackets H to the power of plus sign close square brackets equals 1 comma 77 space cross times space 10 to the power of negative sign 6 end exponent pH equals minus sign log space open square brackets H to the power of plus sign close square brackets pH equals minus sign log space 1 comma 77 space cross times space 10 to the power of negative sign 6 end exponent pH equals 6 minus sign log space 1 comma 77 end style 

Jadi, pH larutan adalah 6 - log 1,77

Perdalam pemahamanmu bersama Master Teacher
di sesi Live Teaching, GRATIS!

2

Iklan

Pertanyaan serupa

Diketahui tetapan ionisasi basa ( K b ​ ) NH 3 ​ adalah 2 x 1 0 − 5 . pH larutan ( NH 4 ​ ) 2 ​ SO 4 ​ 0 , 1 M adalah ....

4

4.7

Jawaban terverifikasi

RUANGGURU HQ

Jl. Dr. Saharjo No.161, Manggarai Selatan, Tebet, Kota Jakarta Selatan, Daerah Khusus Ibukota Jakarta 12860

Coba GRATIS Aplikasi Roboguru

Coba GRATIS Aplikasi Ruangguru

Download di Google PlayDownload di AppstoreDownload di App Gallery

Produk Ruangguru

Hubungi Kami

Ruangguru WhatsApp

+62 815-7441-0000

Email info@ruangguru.com

[email protected]

Contact 02130930000

02130930000

Ikuti Kami

©2026 Ruangguru. All Rights Reserved PT. Ruang Raya Indonesia