Iklan

Pertanyaan

Diketahui lingkaran L berpusat di titik (-2,3} dan melalui titik (1,S}. Jika lingkaran L diputar 90° terhadap titik 0 (0,0) sea rah jarum jam, kemudian digeser ke bawah sejauh S satuan, maka persamaan lingkaran L yang dihasilkan adalah .....

Diketahui lingkaran L berpusat di titik (-2,3} dan melalui titik (1,S}. Jika lingkaran L diputar 90° terhadap titik 0 (0,0) sea rah jarum jam, kemudian
digeser ke bawah sejauh S satuan, maka persamaan lingkaran L yang dihasilkan adalah .....

  1. x squared space plus space y squared space minus space 6 x space plus space 6 y space plus space S space equals space 0

  2. x squared space plus space y squared space minus space 6 x space plus space 6 y space minus space 5 space equals space 0

  3. x squared space plus space y squared space plus space 6 x space minus space 6 y space plus space 5 space equals space 0

  4. x squared space plus space y squared space plus space 6 x space minus space 6 y space minus space 5 space equals space 0

  5. x squared space plus space y squared space plus space 6 x space plus space 5 y space equals space 0

Ikuti Tryout SNBT & Menangkan E-Wallet 100rb

Habis dalam

01

:

12

:

15

:

30

Klaim

Iklan

R. RGFLSATU

Master Teacher

Jawaban terverifikasi

Pembahasan

P u s a t space l i n g k a r a n space left parenthesis negative 2 comma 3 right parenthesis space d i r o t a s i space 90 degree space s e a r a h space j a r u m space j a m comma space b e r a r t i s u d u t space b e r n i l a i space n e g a t i f  open parentheses table row cell x apostrophe end cell row cell y apostrophe end cell end table close parentheses equals open parentheses table row cell cos space left parenthesis negative 90 right parenthesis end cell cell negative sin left parenthesis negative 90 right parenthesis end cell row cell sin space left parenthesis negative 90 right parenthesis end cell cell cos left parenthesis negative 90 right parenthesis end cell end table close parentheses open parentheses table row x row y end table close parentheses  open parentheses table row cell x apostrophe end cell row cell y apostrophe end cell end table close parentheses equals open parentheses table row 0 1 row cell negative 1 end cell 0 end table close parentheses open parentheses table row cell negative 2 end cell row 3 end table close parentheses  open parentheses table row cell x apostrophe end cell row cell y apostrophe end cell end table close parentheses equals open parentheses table row 3 row 2 end table close parentheses  T i t i k space left parenthesis 3 comma 2 right parenthesis space s e l a n j u t n y a space d i t r a n s l a s i space k e space b a w a h space s e j a u h space 5 space s a t u a n  open parentheses table row cell x " end cell row cell y " end cell end table close parentheses equals open parentheses table row 3 row 2 end table close parentheses plus open parentheses table row 0 row cell negative 5 end cell end table close parentheses equals open parentheses table row 3 row cell negative 3 end cell end table close parentheses  P e r s a m a a n space l i n g k a r a n space d e n g a n space p u s a t space space left parenthesis 3 comma negative 3 right parenthesis space m e l a l u i space left parenthesis 1 comma 5 right parenthesis  n i l a i space r space equals space left parenthesis space 1 space minus space left parenthesis space minus 2 right parenthesis right parenthesis space squared space plus space left parenthesis space 5 space minus space 3 right parenthesis space to the power of 2 space end exponent equals space 13  left parenthesis space x space minus space 3 right parenthesis space squared space plus space left parenthesis y space minus space left parenthesis space minus 3 right parenthesis right parenthesis space squared space equals space 13  left parenthesis space x space minus space 3 right parenthesis space to the power of 2 space end exponent plus space left parenthesis y space plus space 3 right parenthesis space squared space equals space 13  equals space x squared space minus space 6 x space plus space 9 space plus space y squared space plus space 6 y space plus space 9  equals space x squared space plus space y squared space minus space 6 x space plus space 6 y space plus space 5

Perdalam pemahamanmu bersama Master Teacher
di sesi Live Teaching, GRATIS!

14

Iklan

Pertanyaan serupa

. Persamaan peta suatu kurva oleh rotasi pusat 0 bersudut 2 π ​ , dilanjutkan dilatasi (0,2} adalah • Persamaan kurva semula adalah ... x = 2 + y − y 2

2

0.0

Jawaban terverifikasi

RUANGGURU HQ

Jl. Dr. Saharjo No.161, Manggarai Selatan, Tebet, Kota Jakarta Selatan, Daerah Khusus Ibukota Jakarta 12860

Coba GRATIS Aplikasi Roboguru

Coba GRATIS Aplikasi Ruangguru

Download di Google PlayDownload di AppstoreDownload di App Gallery

Produk Ruangguru

Hubungi Kami

Ruangguru WhatsApp

+62 815-7441-0000

Email info@ruangguru.com

[email protected]

Contact 02130930000

02130930000

Ikuti Kami

©2025 Ruangguru. All Rights Reserved PT. Ruang Raya Indonesia