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Diketahui kelarutan Ag 3 ​ PO 4 ​ 0,00001 M. Tentukan hasil kali kelarutan .

Diketahui kelarutan  0,00001 M. Tentukan hasil kali kelarutan Ag subscript 3 P O subscript 4.space space space

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I. Solichah

Master Teacher

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hasil kali kelarutan adalah .

hasil kali kelarutan Ag subscript 3 P O subscript 4 adalah 2 comma 7 cross times 10 to the power of negative sign 19 end exponent space bevelled mol to the power of 4 over L to the power of 4.space space space

Pembahasan

Jadi, hasil kali kelarutan adalah .

Ag subscript 3 P O subscript 4 yields 3 Ag to the power of plus sign and P O subscript 4 to the power of 3 minus sign space space space space space s space space space space space space space space space space space 3 s space space space space space space space space space s   K subscript sp space Ag subscript 3 P O subscript 4 equals open square brackets Ag to the power of plus sign close square brackets cubed open square brackets P O subscript 4 to the power of 3 minus sign close square brackets K subscript sp space Ag subscript 3 P O subscript 4 equals open parentheses 3 s close parentheses cubed open parentheses s close parentheses K subscript sp space Ag subscript 3 P O subscript 4 equals 27 s to the power of 4 K subscript sp space Ag subscript 3 P O subscript 4 equals 27 cross times left parenthesis 10 to the power of negative sign 5 end exponent right parenthesis to the power of 4 K subscript sp space Ag subscript 3 P O subscript 4 equals 2 comma 7 cross times 10 to the power of negative sign 19 end exponent space bevelled mol to the power of 4 over L to the power of 4  


Jadi, hasil kali kelarutan Ag subscript 3 P O subscript 4 adalah 2 comma 7 cross times 10 to the power of negative sign 19 end exponent space bevelled mol to the power of 4 over L to the power of 4.space space space

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