Pertanyaan

Diketahui . Jika , maka g − 1 ( x ) = ....

Diketahui $begin mathsize 14px style open parentheses f ring operator h ring operator g close parentheses to the power of negative 1 end exponent open parentheses x close parentheses equals fraction numerator x minus 2 over denominator 4 end fraction end style$ . Jika $begin mathsize 14px style f to the power of negative 1 end exponent open parentheses x close parentheses equals 3 minus 2 x space d a n space h to the power of negative 1 end exponent open parentheses x close parentheses equals fraction numerator 3 minus x over denominator 2 end fraction end style$ , maka $g^{- 1} (x) =$ ....

$begin mathsize 14px style fraction numerator x plus 2 over denominator 4 end fraction end style$
$begin mathsize 14px style fraction numerator x minus 2 over denominator 4 end fraction end style$
2x - 4
2x + 4
4x - 2

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Habis dalam

Klaim

I. Roy

Master Teacher

Mahasiswa/Alumni Universitas Negeri Surabaya

Jawaban terverifikasi

Jawaban

jawabannya B.

Pembahasan

Kita akan lebih mudah mengerjakannya dengan sifat berikut Jadi, jawabannya B.

Kita akan lebih mudah mengerjakannya dengan sifat berikut

$begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell open parentheses f ring operator h ring operator g close parentheses to the power of negative 1 end exponent open parentheses x close parentheses end cell equals cell fraction numerator x minus 2 over denominator 4 end fraction end cell row cell open parentheses g to the power of negative 1 end exponent ring operator h to the power of negative 1 end exponent ring operator f to the power of negative 1 end exponent close parentheses open parentheses x close parentheses end cell equals cell fraction numerator x minus 2 over denominator 4 end fraction end cell row cell g to the power of negative 1 end exponent open parentheses h to the power of negative 1 end exponent open parentheses f to the power of negative 1 end exponent open parentheses x close parentheses close parentheses close parentheses end cell equals cell fraction numerator x minus 2 over denominator 4 end fraction end cell row cell g to the power of negative 1 end exponent open parentheses h to the power of negative 1 end exponent open parentheses 3 minus 2 x close parentheses close parentheses end cell equals cell fraction numerator x minus 2 over denominator 4 end fraction end cell row cell g to the power of negative 1 end exponent open parentheses fraction numerator 3 minus open parentheses 3 minus 2 x close parentheses over denominator 2 end fraction close parentheses end cell equals cell fraction numerator x minus 2 over denominator 4 end fraction end cell row cell g to the power of negative 1 end exponent open parentheses fraction numerator 2 x over denominator 2 end fraction close parentheses end cell equals cell fraction numerator x minus 2 over denominator 4 end fraction end cell row cell g to the power of negative 1 end exponent open parentheses x close parentheses end cell equals cell fraction numerator x minus 2 over denominator 4 end fraction end cell end table end style$

Jadi, jawabannya B.