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Diketahui . Jika , maka g − 1 ( x ) = ....

Diketahui begin mathsize 14px style open parentheses f ring operator h ring operator g close parentheses to the power of negative 1 end exponent open parentheses x close parentheses equals fraction numerator x minus 2 over denominator 4 end fraction end style . Jika begin mathsize 14px style f to the power of negative 1 end exponent open parentheses x close parentheses equals 3 minus 2 x space d a n space h to the power of negative 1 end exponent open parentheses x close parentheses equals fraction numerator 3 minus x over denominator 2 end fraction end style  , maka  ....

  1. begin mathsize 14px style fraction numerator x plus 2 over denominator 4 end fraction end style 

  2. begin mathsize 14px style fraction numerator x minus 2 over denominator 4 end fraction end style 

  3. 24

  4. 2+ 4

  5. 42

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I. Roy

Master Teacher

Mahasiswa/Alumni Universitas Negeri Surabaya

Jawaban terverifikasi

Jawaban

jawabannya B.

jawabannya B.

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Pembahasan

Kita akan lebih mudah mengerjakannya dengan sifat berikut Jadi, jawabannya B.

Kita akan lebih mudah mengerjakannya dengan sifat berikut begin mathsize 14px style open parentheses f ring operator h ring operator g close parentheses to the power of negative 1 end exponent open parentheses x close parentheses equals open parentheses g to the power of negative 1 end exponent ring operator h to the power of negative 1 end exponent ring operator f to the power of negative 1 end exponent close parentheses open parentheses x close parentheses end style 

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell open parentheses f ring operator h ring operator g close parentheses to the power of negative 1 end exponent open parentheses x close parentheses end cell equals cell fraction numerator x minus 2 over denominator 4 end fraction end cell row cell open parentheses g to the power of negative 1 end exponent ring operator h to the power of negative 1 end exponent ring operator f to the power of negative 1 end exponent close parentheses open parentheses x close parentheses end cell equals cell fraction numerator x minus 2 over denominator 4 end fraction end cell row cell g to the power of negative 1 end exponent open parentheses h to the power of negative 1 end exponent open parentheses f to the power of negative 1 end exponent open parentheses x close parentheses close parentheses close parentheses end cell equals cell fraction numerator x minus 2 over denominator 4 end fraction end cell row cell g to the power of negative 1 end exponent open parentheses h to the power of negative 1 end exponent open parentheses 3 minus 2 x close parentheses close parentheses end cell equals cell fraction numerator x minus 2 over denominator 4 end fraction end cell row cell g to the power of negative 1 end exponent open parentheses fraction numerator 3 minus open parentheses 3 minus 2 x close parentheses over denominator 2 end fraction close parentheses end cell equals cell fraction numerator x minus 2 over denominator 4 end fraction end cell row cell g to the power of negative 1 end exponent open parentheses fraction numerator 2 x over denominator 2 end fraction close parentheses end cell equals cell fraction numerator x minus 2 over denominator 4 end fraction end cell row cell g to the power of negative 1 end exponent open parentheses x close parentheses end cell equals cell fraction numerator x minus 2 over denominator 4 end fraction end cell end table end style 

Jadi, jawabannya B.

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