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Diketahui f : x → 5 − 4 x . Jika g ( x ) = ∣ f ( x ) ∣ dan daerah asal f adalah D f ​ = { y ∣ − 2 < x ≤ 3 , y ∈ R } , daerah hasil fungsi y = g ( x ) adalah ...

Diketahui . Jika  dan daerah asal  adalah , daerah hasil fungsi  adalah ...

  1. open curly brackets right enclose x space end enclose space 0 less or equal than y less or equal than 7 comma space y element of straight real numbers close curly brackets

  2. open curly brackets right enclose x space end enclose space 0 less or equal than y less than 7 comma space y element of straight real numbers close curly brackets

  3. open curly brackets right enclose x space end enclose space 0 less than y less or equal than 7 comma space y element of straight real numbers close curly brackets

  4. open curly brackets right enclose x space end enclose space 0 less or equal than y less than 13 comma space y element of straight real numbers close curly brackets

  5. open curly brackets right enclose x space end enclose space 0 less than y less or equal than 13 comma space y element of straight real numbers close curly brackets

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Pembahasan

Fungsi . Daerah asal: Diperoleh daerah hasilnya yaitu: Diperoleh daerah hasilnya yaitu . Daerah hasil fungsi adalah . Jadi, jawaban tidak ada yang tepat.

Fungsi f open parentheses x close parentheses equals 5 minus 4 x.

Daerah asal:

table attributes columnalign right center left columnspacing 0px end attributes row cell D subscript f end cell equals cell open curly brackets right enclose y space end enclose space minus 2 less than x less or equal than 3 comma space y element of straight real numbers close curly brackets end cell row blank equals cell open curly brackets negative 1 comma space 0 comma space 1 comma space 2 comma space 3 close curly brackets end cell end table

Diperoleh daerah hasilnya yaitu:

table attributes columnalign right center left columnspacing 0px end attributes row cell g open parentheses x close parentheses end cell equals cell open vertical bar f open parentheses x close parentheses close vertical bar end cell row cell g open parentheses x close parentheses end cell equals cell open vertical bar 5 minus 4 x close vertical bar end cell row blank blank blank row cell g open parentheses negative 1 close parentheses end cell equals cell open vertical bar 5 minus 4 open parentheses negative 1 close parentheses close vertical bar end cell row blank equals cell open vertical bar 5 plus 4 close vertical bar end cell row blank equals cell open vertical bar 9 close vertical bar end cell row blank equals 9 row blank blank blank row cell g open parentheses 0 close parentheses end cell equals cell open vertical bar 5 minus 4 open parentheses 0 close parentheses close vertical bar end cell row blank equals cell open vertical bar 5 minus 0 close vertical bar end cell row blank equals cell open vertical bar 5 close vertical bar end cell row blank equals 5 row blank blank blank row cell g open parentheses 1 close parentheses end cell equals cell open vertical bar 5 minus 4 open parentheses 1 close parentheses close vertical bar end cell row blank equals cell open vertical bar 5 minus 4 close vertical bar end cell row blank equals cell open vertical bar 1 close vertical bar end cell row blank equals 1 row blank blank blank row cell g open parentheses 2 close parentheses end cell equals cell open vertical bar 5 minus 4 open parentheses 2 close parentheses close vertical bar end cell row blank equals cell open vertical bar 5 minus 8 close vertical bar end cell row blank equals cell open vertical bar negative 3 close vertical bar end cell row blank equals 3 row blank blank blank row cell g open parentheses 3 close parentheses end cell equals cell open vertical bar 5 minus 4 open parentheses 3 close parentheses close vertical bar end cell row blank equals cell open vertical bar 5 minus 12 close vertical bar end cell row blank equals cell open vertical bar negative 7 close vertical bar end cell row blank equals 7 end table

Diperoleh daerah hasilnya yaitu R subscript f equals open curly brackets 1 comma space 3 comma space 5 comma space 7 comma space 9 close curly brackets.

Daerah hasil fungsi y equals g open parentheses x close parentheses adalah R subscript f equals open curly brackets right enclose y space end enclose space 3 less or equal than y less or equal than 9 comma space y element of straight real numbers close curly brackets.

Jadi, jawaban tidak ada yang tepat.

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Diketahui f : x → 3 − x 2 . Jika daerah asal f adalah D f ​ = { x ∣ − 4 < x ≤ 3 , x ∈ R } , daerah hasil fungsi y = ∣ f ( x ) ∣ adalah ...

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