Diketahui harga potensial reduksi dari : 2H++2e−→H2​        Eo=0 voltAl3++3e−→Al         Eo=−1,66 voltZn2++2e−→Zn       Eo=−0,76 voltMg2++2e−→Mg     Eo=−2,37 voltCu2++2e−→Cu      Eo=+0,34 volt  Notasi sel yang berlangsung spontan adaiah ....

Pertanyaan

Diketahui harga potensial reduksi dari :

2 H to the power of plus sign and 2 e to the power of minus sign yields H subscript 2 space space space space space space space space E to the power of o equals 0 space volt Al to the power of 3 plus sign and 3 e to the power of minus sign yields Al space space space space space space space space space E to the power of o equals minus sign 1 comma 66 space volt Zn to the power of 2 plus sign and 2 e to the power of minus sign yields Zn space space space space space space space E to the power of o equals minus sign 0 comma 76 space volt Mg to the power of 2 plus sign and 2 e to the power of minus sign yields Mg space space space space space E to the power of o equals minus sign 2 comma 37 space volt Cu to the power of 2 plus sign and 2 e to the power of minus sign yields Cu space space space space space space E to the power of o equals plus 0 comma 34 space volt 

Notasi sel yang berlangsung spontan adaiah ....

  1. Cu forward slash Cu to the power of 2 plus sign forward slash forward slash H to the power of plus sign forward slash H subscript 2 

  2. Mg forward slash Mg to the power of 2 plus sign forward slash forward slash Cu to the power of 2 plus sign forward slash Cu 

  3. Ag forward slash Ag to the power of plus sign forward slash forward slash Al to the power of 3 plus sign forward slash Al  

  4. H subscript 2 forward slash 2 H to the power of plus sign forward slash forward slash Al to the power of 3 plus sign forward slash Al 

  5. Zn forward slash Zn to the power of 2 plus sign forward slash forward slash Mg to the power of 2 plus sign forward slash Mg 

S. Lubis

Master Teacher

Jawaban terverifikasi

Pembahasan

E to the power of 0 sel greater than 0 , maka reaksi berlangsung spontan.

E to the power of 0 sel equals E to the power of 0 red minus sign E to the power of 0 oks 

table attributes columnalign right center left columnspacing 0px end attributes row cell A right parenthesis space E to the power of 0 sel end cell equals cell E to the power of 0 subscript H to the power of plus sign end subscript minus sign E to the power of 0 subscript Cu end cell row blank equals cell 0 minus sign 0 comma 34 end cell row blank equals cell negative sign 0 comma 34 end cell row cell B right parenthesis space E to the power of 0 sel end cell equals cell E to the power of 0 subscript Cu minus sign E to the power of 0 subscript Mg end cell row blank equals cell 0 comma 34 minus sign left parenthesis minus sign 2 comma 37 right parenthesis end cell row blank equals cell plus 2 comma 71 end cell row cell C right parenthesis space E to the power of 0 sel end cell equals cell E to the power of 0 subscript Al minus sign E to the power of 0 subscript Ag end cell row blank equals cell negative sign 1 comma 66 minus sign left parenthesis 0 comma 79 right parenthesis end cell row blank equals cell negative sign 2 comma 45 end cell row cell D right parenthesis space E to the power of 0 sel end cell equals cell E to the power of 0 subscript Al minus sign E to the power of 0 subscript H end cell row blank equals cell negative sign 1 comma 66 minus sign 0 end cell row blank equals cell negative sign 1 comma 66 end cell row cell E right parenthesis space E to the power of 0 sel end cell equals cell E to the power of 0 subscript Mg minus sign E to the power of 0 subscript Zn end cell row blank equals cell negative sign 2 comma 37 minus sign left parenthesis minus sign 0 comma 76 right parenthesis end cell row blank equals cell negative sign 1 comma 61 end cell end table 

Maka, jawaban yang sesuai adalah B

338

5.0 (2 rating)

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Mn2+ + 2e− → Mn        E0=−1,8 VoltFe2+  + 2e− → Fe        E0 = − 0,44 Volt  Tentukan a. E0 sel? b. Notasi sel/diagram sel? c. Reaksi selnya?

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