Pertanyaan

Diketahui fungsi f ( 2 x + 1 ) = 2 x − 3 x − 5 , x  = 2 3 dan g ( x ) = x − 4 x + 6 , x  = 4 .Tentukan rumus fungsi: a. ( f + g ) ( x ) .

Diketahui fungsi $f (2 x + 1) = \frac{x - 5}{2 x - 3}, x \neq = \frac{3}{2}$ dan $g (x) = \frac{x + 6}{x - 4}, x \neq = 4$ . Tentukan rumus fungsi:

a. $(f + g) (x)$ .

P. Afrisno

Master Teacher

Mahasiswa/Alumni Universitas Sebelas Maret

Jawaban terverifikasi

Jawaban

diperoleh .

diperoleh $begin mathsize 14px style open parentheses f plus g close parentheses open parentheses x close parentheses equals fraction numerator 3 x minus 5 over denominator 2 x minus 8 end fraction end style$ .

Pembahasan

Dengan demikian, diperoleh .

$table attributes columnalign right center left columnspacing 0px end attributes row blank blank cell size 14px f begin mathsize 14px style left parenthesis 2 x plus 1 right parenthesis end style size 14px equals fraction numerator size 14px x size 14px minus size 14px 5 over denominator size 14px 2 size 14px x size 14px minus size 14px 3 end fraction end cell row cell size 14px f begin mathsize 14px style left parenthesis 2 x plus 1 right parenthesis end style end cell size 14px equals cell fraction numerator begin display style size 14px 1 over size 14px 2 end style begin mathsize 14px style left parenthesis 2 x plus 1 right parenthesis end style size 14px minus begin display style size 14px 11 over size 14px 2 end style over denominator begin mathsize 14px style left parenthesis 2 x plus 1 right parenthesis end style size 14px minus size 14px 4 end fraction end cell row cell size 14px f size 14px left parenthesis size 14px x size 14px right parenthesis end cell size 14px equals cell fraction numerator begin display style size 14px 1 over size 14px 2 end style size 14px x size 14px minus begin display style size 14px 11 over size 14px 2 end style over denominator size 14px x size 14px minus size 14px 4 end fraction end cell row cell size 14px f size 14px left parenthesis size 14px x size 14px right parenthesis end cell size 14px equals cell fraction numerator size 14px x size 14px minus size 14px 11 over denominator size 14px 2 size 14px x size 14px minus size 14px 8 end fraction end cell row cell begin mathsize 14px style left parenthesis f plus g right parenthesis end style begin mathsize 14px style left parenthesis x right parenthesis end style end cell size 14px equals cell fraction numerator size 14px x size 14px minus size 14px 11 over denominator size 14px 2 size 14px x size 14px minus size 14px 8 end fraction size 14px plus fraction numerator size 14px x size 14px plus size 14px 6 over denominator size 14px x size 14px minus size 14px 4 end fraction end cell row blank size 14px equals cell fraction numerator size 14px x size 14px minus size 14px 11 size 14px plus size 14px 2 begin mathsize 14px style left parenthesis x plus 6 right parenthesis end style over denominator size 14px 2 size 14px x size 14px minus size 14px 8 end fraction end cell row blank size 14px equals cell fraction numerator size 14px 3 size 14px x size 14px minus size 14px 5 over denominator size 14px 2 size 14px x size 14px minus size 14px 8 end fraction end cell end table$

Dengan demikian, diperoleh $begin mathsize 14px style open parentheses f plus g close parentheses open parentheses x close parentheses equals fraction numerator 3 x minus 5 over denominator 2 x minus 8 end fraction end style$ .

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