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Diketahui f : R → R dan g : R → R didefinisikan dengan f ( x ) = x − 5 3 x + 1 ​ , x  = 5 dan g ( x ) = x - 3. lnvers dari ( f o g )( x ) adalah ....

Diketahui f : R → R dan g : R → R didefinisikan dengan dan g(x) = x - 3. lnvers dari (f o g)(x) adalah ....

  1. begin mathsize 14px style left parenthesis f o g right parenthesis to the power of negative 1 space end exponent left parenthesis x right parenthesis equals fraction numerator negative 8 x plus 8 over denominator x minus 3 end fraction comma space x not equal to 3 end style

  2. begin mathsize 14px style left parenthesis f o g right parenthesis to the power of negative 1 space end exponent left parenthesis x right parenthesis equals fraction numerator negative 3 x plus 8 over denominator x plus 8 end fraction comma space x not equal to negative 8 end style

  3. begin mathsize 14px style left parenthesis f o g right parenthesis to the power of negative 1 space end exponent left parenthesis x right parenthesis equals fraction numerator 3 x minus 8 over denominator x minus 8 end fraction comma space x not equal to 8 end style

  4. begin mathsize 14px style left parenthesis f o g right parenthesis to the power of negative 1 space end exponent left parenthesis x right parenthesis equals fraction numerator 8 x minus 8 over denominator x minus 3 end fraction comma space x not equal to 3 end style

  5. begin mathsize 14px style left parenthesis f o g right parenthesis to the power of negative 1 space end exponent left parenthesis x right parenthesis equals fraction numerator 8 x plus 8 over denominator x plus 3 end fraction comma space x not equal to negative 3 end style

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S. Intan

Master Teacher

Mahasiswa/Alumni Institut Pertanian Bogor

Jawaban terverifikasi

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Pembahasan

begin mathsize 14px style left parenthesis fog right parenthesis left parenthesis straight x right parenthesis equals straight f left parenthesis straight g left parenthesis straight x right parenthesis right parenthesis  space space space space space space space space space space space space space equals straight f left parenthesis straight x minus 3 right parenthesis  space space space space space space space space space space space space space equals fraction numerator 3 open parentheses straight x minus 3 close parentheses plus 1 over denominator straight x minus 3 minus 5 end fraction  space space space space space space space space space space space space space equals fraction numerator 3 straight x minus 8 over denominator straight x minus 8 end fraction    Untuk space straight f open parentheses straight x close parentheses equals fraction numerator ax plus straight b over denominator cx plus straight d end fraction space maka space inversnya colon  straight f to the power of negative 1 end exponent open parentheses straight x close parentheses equals fraction numerator negative dx plus straight b over denominator cx minus straight a end fraction    Jadi comma space invers space dari space left parenthesis fog right parenthesis left parenthesis straight x right parenthesis equals fraction numerator 3 straight x minus 8 over denominator straight x minus 8 end fraction space adalah  open parentheses fog close parentheses to the power of negative 1 end exponent open parentheses straight x close parentheses equals fraction numerator 8 straight x minus 8 over denominator straight x minus 3 end fraction  dengan space syarat colon space  straight x minus 3 not equal to 0 space  straight x not equal to 3 end style

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Mabel Pines

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Andreas Pratama Syahputra

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