Roboguru

Pertanyaan

Diketahui data dari reaksi kesetimbangan:

2 N O left parenthesis g right parenthesis plus O subscript 2 left parenthesis g right parenthesis rightwards arrow over leftwards arrow 2 N O subscript 2 left parenthesis g right parenthesis sebagai berikut:

Tetapan kesetimbangan (Kc) dari reaksi tersebut adalah ....

  1. K c equals fraction numerator left square bracket 2 right square bracket squared left square bracket 2 right square bracket squared over denominator left square bracket 4 right square bracket end fraction

  2. K c equals fraction numerator left square bracket 2 right square bracket squared over denominator left square bracket 2 right square bracket squared left square bracket 4 right square bracket end fraction

  3. K c equals left square bracket 2 right square bracket squared left square bracket 4 right square bracket left square bracket 2 right square bracket squared

  4. K c equals fraction numerator left square bracket 2 right square bracket left square bracket 4 right square bracket over denominator left square bracket 2 right square bracket squared end fraction

  5. K c equals fraction numerator left square bracket 4 right square bracket over denominator left square bracket 2 right square bracket squared left square bracket 2 right square bracket end fraction

A. Ratna

Master Teacher

Mahasiswa/Alumni Universitas Negeri Malang

Jawaban terverifikasi

Pembahasan

H a r g a space t e t a p a n space k e s e t i m b a n g a n space left parenthesis K c right parenthesis comma space m e r u p a k a n colon  K c equals fraction numerator left square bracket N O subscript 2 right square bracket squared over denominator left square bracket N O right square bracket squared left square bracket O subscript 2 right square bracket end fraction equals fraction numerator left square bracket 2 right square bracket squared over denominator left square bracket 2 right square bracket squared left square bracket 4 right square bracket end fraction

11

0.0 (0 rating)

Pertanyaan serupa

CO(g)​+H2​O⇌CO2(g)​+H2(g)​ Bila 1 mol CO dan 1 mol H2​O direaksikan sampai terjadi kesetimbangan, dan pada saat tersebut masih tersisa 0,2 mol CO, maka harga tetapan kesetimbangan Kc adalah ….

6rb+

0.0

Jawaban terverifikasi

RUANGGURU HQ

Jl. Dr. Saharjo No.161, Manggarai Selatan, Tebet, Kota Jakarta Selatan, Daerah Khusus Ibukota Jakarta 12860

Coba GRATIS Aplikasi Ruangguru

Produk Ruangguru

Produk Lainnya

Hubungi Kami

Ruangguru WhatsApp

081578200000

Email info@ruangguru.com

info@ruangguru.com

Contact 02140008000

02140008000

Ikuti Kami

©2022 Ruangguru. All Rights Reserved PT. Ruang Raya Indonesia