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Diketahui g ( x ) = 2 x + 4 dan f ∘ g ( x ) = 4 x 2 + 16 x − 3 Tentukan Nilai dari f − 1 ( − 1 ) .

Diketahui  dan
Tentukan Nilai dari .

  1. ...space 

  2. ...begin mathsize 14px style space end style 

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R. RGFLSATU

Master Teacher

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nilai .

nilai begin mathsize 14px style bold italic f to the power of bold minus bold 1 end exponent bold left parenthesis bold minus bold 1 bold right parenthesis bold equals bold 3 square root of bold 2 end style

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Ingat: konsep komposisi dua fungsi Diketahui: dan Maka , Maka : Ingat : Sehingga: Jadi, nilai .

Ingat: konsep komposisi dua fungsi begin mathsize 14px style f ring operator g open parentheses x close parentheses equals f open parentheses g open parentheses x close parentheses close parentheses end style 

Diketahui: undefined dan size 14px g size 14px left parenthesis size 14px x size 14px right parenthesis size 14px equals size 14px 2 size 14px x size 14px plus size 14px 4
Maka

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell f ring operator g open parentheses x close parentheses end cell equals cell 4 x squared plus 16 x minus 3 end cell row cell f left parenthesis g left parenthesis x right parenthesis right parenthesis end cell equals cell 4 x squared plus 16 x minus 3 end cell row cell f left parenthesis 2 x plus 4 right parenthesis end cell equals cell 4 x squared plus 16 x minus 3 end cell end table end style 

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row blank blank Misal end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank colon end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank space end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank y end table table attributes columnalign right center left columnspacing 0px end attributes row blank equals blank end table table attributes columnalign right center left columnspacing 0px end attributes row cell 2 x plus 4 end cell left right double arrow cell x equals fraction numerator y minus 4 over denominator 2 end fraction end cell end table end style,
Maka :

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell f left parenthesis y right parenthesis end cell equals cell 4 times left parenthesis fraction numerator y minus 4 over denominator 2 end fraction right parenthesis squared plus 16 times left parenthesis fraction numerator y minus 4 over denominator 2 end fraction right parenthesis minus 3 end cell row blank equals cell 4 times left parenthesis fraction numerator y squared minus 8 y plus 16 over denominator 4 end fraction right parenthesis plus 8 y minus 32 minus 3 end cell row blank equals cell y squared minus 8 y plus 16 plus 8 y minus 35 end cell row blank equals cell y squared minus 19 end cell end table end style

Ingat : begin mathsize 14px style f left parenthesis x right parenthesis equals x squared minus b left right double arrow f to the power of negative 1 end exponent left parenthesis x right parenthesis equals square root of x plus b end root end style  
Sehingga:
begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell f to the power of negative 1 end exponent left parenthesis y right parenthesis end cell equals cell square root of negative 1 plus 19 end root end cell row cell f to the power of negative 1 end exponent left parenthesis negative 1 right parenthesis end cell equals cell square root of negative 1 plus 19 end root end cell row blank equals cell square root of 18 end cell row blank equals cell 3 square root of 2 end cell end table end style  

Jadi, nilai begin mathsize 14px style bold italic f to the power of bold minus bold 1 end exponent bold left parenthesis bold minus bold 1 bold right parenthesis bold equals bold 3 square root of bold 2 end style

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Diketahui f ( x ) = x 1 ​ dan g ( x ) = x − 1 . Jika ( f ∘ g ) − 1 ( x ) = 0 Tentukan nilai dari x !

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