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Pertanyaan

Diketahui u = ( 12 , 11 ) dan v = ( 2 , 14 ) . Tentukan nilai 4 u − 5 v .

Diketahui  dan . Tentukan nilai .

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A. Armanda

Master Teacher

Mahasiswa/Alumni Universitas Indraprasta PGRI

Jawaban terverifikasi

Jawaban

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 table attributes columnalign right center left columnspacing 0px end attributes row blank blank 4 end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank cell u with rightwards arrow on top end cell end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank minus end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank 5 end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank cell v with rightwards arrow on top end cell end table table attributes columnalign right center left columnspacing 0px end attributes row blank equals blank end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank cell open parentheses 38 comma space minus 26 close parentheses end cell end table.

Pembahasan

Ingat! Diketahui dan , maka : Jadi, .

Ingat!

table attributes columnalign right center left columnspacing 0px end attributes row cell a with rightwards arrow on top end cell equals cell open parentheses table row cell a subscript 1 end cell row cell a subscript 2 end cell end table close parentheses end cell row cell k times a with rightwards arrow on top end cell equals cell open parentheses table row cell k a subscript 1 end cell row cell k a subscript 2 end cell end table close parentheses end cell end table 

Diketahui u with rightwards arrow on top equals open parentheses 12 comma space 11 close parentheses dan v with rightwards arrow on top equals open parentheses 2 comma space 14 close parentheses, maka 4 u with rightwards arrow on top minus 5 v with rightwards arrow on top:

table attributes columnalign right center left columnspacing 0px end attributes row cell 4 u with rightwards arrow on top minus 5 v with rightwards arrow on top end cell equals cell 4 open parentheses table row 12 row 11 end table close parentheses minus 5 open parentheses table row 2 row 14 end table close parentheses end cell row blank equals cell open parentheses table row cell 4 times 12 end cell row cell 4 times 11 end cell end table close parentheses minus open parentheses table row cell 5 times 2 end cell row cell 5 times 14 end cell end table close parentheses end cell row blank equals cell open parentheses table row cell 48 minus 10 end cell row cell 44 minus 70 end cell end table close parentheses end cell row blank equals cell open parentheses table row 38 row cell negative 26 end cell end table close parentheses end cell end table 

Jadi, table attributes columnalign right center left columnspacing 0px end attributes row blank blank 4 end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank cell u with rightwards arrow on top end cell end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank minus end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank 5 end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank cell v with rightwards arrow on top end cell end table table attributes columnalign right center left columnspacing 0px end attributes row blank equals blank end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank cell open parentheses 38 comma space minus 26 close parentheses end cell end table.

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Diketahui vektor p ​ = ( 3 4 ​ ) , vektor q ​ = ( 5 − 1 ​ ) , dan vektor r = ( − 2 6 ​ ) . Tentukan: b) p ​ + 2 q ​ − 3 r

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