Roboguru

Diketahui a=(−4−5​), b=(62​), dan c=(3−4​). Hitunglah: b.   b−2c;

Pertanyaan

Diketahui begin mathsize 14px style bold a equals open parentheses table row cell negative 4 end cell row cell negative 5 end cell end table close parentheses end stylebegin mathsize 14px style bold b equals open parentheses table row 6 row 2 end table close parentheses end style, dan begin mathsize 14px style bold c equals open parentheses table row 3 row cell negative 4 end cell end table close parentheses end style. Hitunglah:

b.   begin mathsize 14px style bold b minus 2 bold c end style;

  1. .... 

  2. .... 

Pembahasan Soal:

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell bold b minus 2 bold c end cell equals cell open parentheses table row 6 row 2 end table close parentheses minus 2 open parentheses table row 3 row cell negative 4 end cell end table close parentheses end cell row blank equals cell open parentheses table row 6 row 2 end table close parentheses minus open parentheses table row 6 row cell negative 8 end cell end table close parentheses end cell row blank equals cell open parentheses table row cell 6 minus 6 end cell row cell 2 minus left parenthesis negative 8 right parenthesis end cell end table close parentheses end cell row blank equals cell open parentheses table row 0 row 10 end table close parentheses end cell end table end style

Pembahasan terverifikasi oleh Roboguru

Dijawab oleh:

A. Acfreelance

Terakhir diupdate 05 Oktober 2021

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Pertanyaan yang serupa

Diketahui matriks P=(2−1​−36​), Q=(−28​52​), dan R=(54​1−2​). Tentukan: a. P+R

Pembahasan Soal:

Diketahui matriks straight P equals open parentheses table row 2 cell negative 3 end cell row cell negative 1 end cell 6 end table close parentheses, Q equals open parentheses table row cell negative 2 end cell 5 row 8 2 end table close parentheses, dan straight R equals open parentheses table row 5 1 row 4 cell negative 2 end cell end table close parentheses. Maka straight P plus straight R adalah

table attributes columnalign right center left columnspacing 0px end attributes row cell straight P plus straight R end cell equals cell open parentheses table row 2 cell negative 3 end cell row cell negative 1 end cell 6 end table close parentheses plus open parentheses table row 5 1 row 4 cell negative 2 end cell end table close parentheses end cell row blank equals cell open parentheses table row 7 cell negative 2 end cell row 3 4 end table close parentheses end cell end table

Jadi, table attributes columnalign right center left columnspacing 0px end attributes row cell straight P plus straight R end cell equals cell open parentheses table row 7 cell negative 2 end cell row 3 4 end table close parentheses end cell end table.

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Roboguru

Diketahui vektor u=3i+6j​,v=−9i+12j​, dan w=8i−2j​. Tentukan: 2u+v+w

Pembahasan Soal:

Dari soal, akan didapatkan hasil operasi vektor tersebut sebagai berikut:

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell 2 u with bar on top plus v with bar on top plus w with bar on top end cell equals cell 2 open parentheses table row 3 row 6 end table close parentheses plus open parentheses table row cell negative 9 end cell row 12 end table close parentheses plus open parentheses table row 8 row cell negative 2 end cell end table close parentheses end cell row blank equals cell open parentheses table row 5 row 22 end table close parentheses end cell end table end style 

Sehingga hasil penjumlahan vektor tersebut adalah begin mathsize 14px style 5 straight i with rightwards arrow on top plus 22 straight j with rightwards arrow on top end style 

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Roboguru

Diketahui vektor-vektor a=2i−3j​,b=−4i−j​,danc=−i+2j​. Nyatakan setiap vektor berikut ke dalam vektor satuan idanj​ dan tentukan besarnya. a. a+b+c

Pembahasan Soal:

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell a with rightwards arrow on top plus b with rightwards arrow on top plus c with rightwards arrow on top end cell equals cell open parentheses 2 i with rightwards arrow on top minus 3 j with rightwards arrow on top close parentheses plus open parentheses negative 4 i with rightwards arrow on top minus j with rightwards arrow on top close parentheses plus open parentheses negative i with rightwards arrow on top plus 2 j with rightwards arrow on top close parentheses end cell row blank equals cell negative 3 i with rightwards arrow on top minus 2 j with rightwards arrow on top end cell end table end style

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell open vertical bar a with rightwards arrow on top plus b with rightwards arrow on top plus c with rightwards arrow on top close vertical bar end cell equals cell square root of open parentheses negative 3 close parentheses squared plus open parentheses negative 2 close parentheses squared end root end cell row blank equals cell square root of 9 plus 4 end root end cell row blank equals cell square root of 13 end cell end table end style 

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Roboguru

Diketahui vektor-vektor a=i+2j​, b=3i+j​, dan c=i+9j​. Tentukan: c. a+b+c

Pembahasan Soal:

Penjumlahan vektor secara aljabar dengan menjumlahkan unsur-unsur yang seletak.

Diketahui vektor-vektor a with rightwards arrow on top equals i with rightwards arrow on top plus 2 j with rightwards arrow on topb with rightwards arrow on top equals 3 i with rightwards arrow on top plus j with rightwards arrow on top, dan c with rightwards arrow on top equals i with rightwards arrow on top plus 9 j with rightwards arrow on top, akan ditentukan a with rightwards arrow on top plus b with rightwards arrow on top plus c with rightwards arrow on top.

Perhatikan perhitungan berikut.

table attributes columnalign right center left columnspacing 2px end attributes row cell a with rightwards arrow on top plus b with rightwards arrow on top plus c with rightwards arrow on top end cell equals cell open parentheses i with rightwards arrow on top plus 2 j with rightwards arrow on top close parentheses plus open parentheses 3 i with rightwards arrow on top plus j with rightwards arrow on top close parentheses plus open parentheses i with rightwards arrow on top plus 9 j with rightwards arrow on top close parentheses end cell row blank equals cell open parentheses 1 plus 3 plus 1 close parentheses i with rightwards arrow on top plus open parentheses 2 plus 1 plus 9 close parentheses j with rightwards arrow on top end cell row blank equals cell 5 i with rightwards arrow on top plus 12 j with rightwards arrow on top end cell end table

Jadi, diperoleh a with rightwards arrow on top plus b with rightwards arrow on top plus c with rightwards arrow on top equals 5 i with rightwards arrow on top plus 12 j with rightwards arrow on top.

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Roboguru

Diketahui a=(−4−5​), b=(62​), dan c=(3−4​). Hitunglah: c.   3a−b−c.

Pembahasan Soal:

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell 3 bold a minus bold b minus bold c end cell equals cell 3 open parentheses table row cell negative 4 end cell row cell negative 5 end cell end table close parentheses minus open parentheses table row 6 row 2 end table close parentheses minus open parentheses table row 3 row cell negative 4 end cell end table close parentheses end cell row blank equals cell open parentheses table row cell negative 12 end cell row cell negative 15 end cell end table close parentheses minus open parentheses table row 6 row 2 end table close parentheses minus open parentheses table row 3 row cell negative 4 end cell end table close parentheses end cell row blank equals cell open parentheses table row cell negative 12 minus 6 minus 3 end cell row cell negative 15 minus 2 minus left parenthesis negative 4 right parenthesis end cell end table close parentheses end cell row blank equals cell open parentheses table row cell negative 21 end cell row cell negative 13 end cell end table close parentheses end cell end table end style

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Roboguru

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