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Diketahui a=4, b=2, dan c=21​. Nilai (a−1)2×c−3b4​ adalah ....

Pertanyaan

Diketahui a=4, b=2, dan c=1 half. Nilai open parentheses a to the power of negative 1 end exponent close parentheses squared cross times b to the power of 4 over c to the power of negative 3 end exponent adalah ....

  1. 1 over 8

  2. 1 over 8

  3. 1 half

  4. 2

  5. 2596 over 125

F. Pratama

Master Teacher

Mahasiswa/Alumni Universitas Putra Indonesia YPTK Padang

Jawaban terverifikasi

Pembahasan

open parentheses a to the power of negative 1 end exponent close parentheses squared cross times b to the power of 4 over c to the power of negative 3 end exponent equals fraction numerator b to the power of 4 c cubed over denominator a squared end fraction  equals fraction numerator 2 to the power of 4 open parentheses begin display style 1 half end style close parentheses cubed over denominator 4 squared end fraction  equals fraction numerator 16 open parentheses begin display style 1 over 8 end style close parentheses over denominator 16 end fraction  equals 1 over 8

1rb+

5.0 (3 rating)

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Sederhanakan dan hitunglah. a. (x5​)−2⋅(3x25​)7÷(2x5​)−4

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