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Diberikan . Jika untuk x = - 1 fungsi f(x) bernilai 14 dan untuk x = 1 fungsi f(x) bernilai 6, maka f(x) = ...

Diberikan begin mathsize 12px style f " open parentheses x close parentheses equals 12 x squared minus 30 x end style . Jika untuk x = - 1 fungsi f(x) bernilai 14 dan untuk x = 1 fungsi f(x) bernilai 6, maka f(x) = ...

  1. begin mathsize 12px style f open parentheses x close parentheses equals x to the power of 4 minus 5 x cubed plus 2 x plus 8 end style  

  2. begin mathsize 12px style f open parentheses x close parentheses equals x to the power of 4 minus 5 x cubed plus 2 x plus 9 end style  

  3. begin mathsize 12px style f open parentheses x close parentheses equals x to the power of 4 minus 5 x cubed plus x end style  

  4. begin mathsize 12px style f open parentheses x close parentheses equals x to the power of 4 minus 5 x cubed plus x plus 9 end style  

  5. begin mathsize 12px style f open parentheses x close parentheses equals x to the power of 4 minus 5 x cubed plus x plus 8 end style  

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F. Kurnia

Master Teacher

Mahasiswa/Alumni Universitas Jember

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Eliminasi persamaan (1) dan (2) didapat A = 1, B = 9

begin mathsize 12px style f " open parentheses x close parentheses equals 12 x squared minus 30 x f apostrophe open parentheses x close parentheses equals integral open parentheses 12 x squared minus 30 x close parentheses space d x f apostrophe open parentheses x close parentheses equals 12 over 3 x cubed minus 30 over 2 x squared plus A f apostrophe open parentheses x close parentheses equals 4 x cubed minus 15 x squared plus A comma space A space a d a l a h space k o n s tan t a  f open parentheses x close parentheses equals integral open parentheses 4 x cubed minus 15 x squared plus A close parentheses space d x f open parentheses x close parentheses equals 4 over 4 x to the power of 4 minus 15 over 3 x cubed plus A x plus B f open parentheses x close parentheses equals x to the power of 4 minus 5 x cubed plus A x plus B comma space B space a d a l a h space k o n s tan t a  f open parentheses negative 1 close parentheses equals 14 open parentheses negative 1 close parentheses to the power of 4 minus 5 open parentheses negative 1 close parentheses cubed plus A open parentheses negative 1 close parentheses plus B equals 14 1 plus 5 minus A plus B equals 14 minus A plus B equals 8 space space horizontal ellipsis space space open parentheses 1 close parentheses  f open parentheses 1 close parentheses equals 6 open parentheses 1 close parentheses to the power of 4 minus 5 open parentheses 1 close parentheses cubed plus A open parentheses 1 close parentheses plus B equals 6 minus 4 plus A plus B equals 6 A plus B equals 10 space space horizontal ellipsis space space open parentheses 2 close parentheses end style     

 

Eliminasi persamaan (1) dan (2) didapat A = 1, B = 9

begin mathsize 12px style therefore space f open parentheses x close parentheses equals x to the power of 4 minus 5 x cubed plus x plus 9 end style  

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