Pertanyaan

Diberikan fungsi f : R × R → R dengan . Nilai fungsi f ( x , y ) jika x = − 3 dan y = 7 adalah ....

Diberikan fungsi $f : R \times R \to R$ dengan $size 14px f begin mathsize 14px style left parenthesis x comma y right parenthesis end style size 14px equals fraction numerator size 14px minus size 14px 2 size 14px x to the power of size 14px 2 size 14px plus size 14px 5 size 14px y size 14px minus size 14px 11 over denominator size 14px x size 14px minus size 14px 2 size 14px y to the power of size 14px 2 size 14px plus size 14px 2 end fraction$ . Nilai fungsi $f (x, y)$ jika $x = - 3$ dan $y = 7$ adalah ....

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Klaim

I. Roy

Master Teacher

Mahasiswa/Alumni Universitas Negeri Surabaya

Jawaban terverifikasi

Jawaban

jawabannya adalah B.

Pembahasan

Dari soal, diberikan fungsi dengan . Akan dicari nilai fungsi jika dan . Subtitusi dan , didapat Jadi jawabannya adalah B.

Dari soal, diberikan fungsi dengan $size 14px f begin mathsize 14px style left parenthesis x comma y right parenthesis end style size 14px equals fraction numerator size 14px minus size 14px 2 size 14px x to the power of size 14px 2 size 14px plus size 14px 5 size 14px y size 14px minus size 14px 11 over denominator size 14px x size 14px minus size 14px 2 size 14px y to the power of size 14px 2 size 14px plus size 14px 2 end fraction$ . Akan dicari nilai fungsi jika dan .

Subtitusi dan , didapat

$table attributes columnalign right center left columnspacing 0px end attributes row cell size 14px f begin mathsize 14px style left parenthesis negative 3 , space 7 right parenthesis end style end cell size 14px equals cell fraction numerator size 14px minus size 14px 2 begin mathsize 14px style left parenthesis negative 3 right parenthesis end style to the power of size 14px 2 size 14px plus size 14px 5 begin mathsize 14px style left parenthesis 7 right parenthesis end style size 14px minus size 14px 11 over denominator begin mathsize 14px style left parenthesis negative 3 right parenthesis end style size 14px minus size 14px 2 begin mathsize 14px style left parenthesis 7 right parenthesis end style to the power of size 14px 2 size 14px plus size 14px 2 end fraction end cell row blank size 14px equals cell fraction numerator size 14px minus size 14px 2 begin mathsize 14px style left parenthesis 9 right parenthesis end style size 14px plus size 14px 35 size 14px minus size 14px 11 over denominator begin mathsize 14px style left parenthesis negative 3 right parenthesis end style size 14px minus size 14px 2 begin mathsize 14px style left parenthesis 49 right parenthesis end style size 14px plus size 14px 2 end fraction end cell row blank size 14px equals cell fraction numerator size 14px minus size 14px 18 size 14px plus size 14px 35 size 14px minus size 14px 11 over denominator begin mathsize 14px style left parenthesis negative 3 right parenthesis end style size 14px minus size 14px 98 size 14px plus size 14px 2 end fraction end cell row blank size 14px equals cell fraction numerator size 14px 6 over denominator size 14px minus size 14px 99 end fraction end cell row blank size 14px equals cell size 14px minus size 14px 2 over size 14px 33 end cell end table$

Jadi jawabannya adalah B.