Roboguru

Dari reaksi :  Pada suhu tetap diperoleh data sebagai berikut :   Rumus laju reaksi dari data di atas adalah ....

Pertanyaan

Dari reaksi : 2 space Fe to the power of 3 plus sign open parentheses aq close parentheses space plus space 3 space S to the power of 2 minus sign open parentheses aq close parentheses space rightwards arrow space S open parentheses s close parentheses space plus space 2 space Fe S open parentheses s close parentheses

Pada suhu tetap diperoleh data sebagai berikut :
 


Rumus laju reaksi dari data di atas adalah ....space 

  1. v double bond k space open square brackets Fe to the power of 3 plus sign close square brackets squared space open square brackets S to the power of 2 minus sign close square brackets squaredspace 

  2. v double bond k space open square brackets Fe to the power of 3 plus sign close square brackets squared space open square brackets S to the power of 2 minus sign close square brackets cubedspace 

  3. v double bond k space open square brackets Fe to the power of 3 plus sign close square brackets squared space open square brackets S to the power of 2 minus sign close square bracketsspace 

  4. v double bond k space open square brackets Fe to the power of 3 plus sign close square brackets space open square brackets S to the power of 2 minus sign close square brackets squaredspace 

  5. v double bond k space open square brackets Fe to the power of 3 plus sign close square brackets space open square brackets S to the power of 2 minus sign close square bracketsspace 

Pembahasan Soal:

Secara umum persamaan laju reaksi dapat dituliskan sebagai berikut.


v double bond k open square brackets pereaksi close square brackets to the power of x  Keterangan space colon v double bond laju space reaksi k double bond tetapan space laju space reaksi x double bond orde space reaksi


Untuk menyelesaikan soal diatas, maka perlu dicari terlebih dahulu orde reaksinya.

TIPS! Untuk menentukan orde reaksi terhadap open square brackets Fe cubed to the power of plus close square brackets maka gunakan data percobaan yang open square brackets S to the power of 2 minus sign close square bracketsnya sama, dan begitupun sebaliknya.

  • Orde reaksi terhadap open square brackets Fe cubed to the power of plus close square brackets, gunakan data percobaan 1 dan 2


table attributes columnalign right center left columnspacing 0px end attributes row v equals cell k open square brackets Fe to the power of 3 plus sign close square brackets to the power of x middle dot open square brackets S to the power of 2 minus sign close square brackets to the power of y end cell row blank blank blank row cell v subscript 1 over v subscript 2 end cell equals cell fraction numerator k open square brackets Fe to the power of 3 plus sign close square brackets subscript 1 to the power of x middle dot open square brackets S to the power of 2 minus sign close square brackets subscript 1 to the power of y over denominator k open square brackets Fe to the power of 3 plus sign close square brackets subscript 2 to the power of x middle dot open square brackets S to the power of 2 minus sign close square brackets subscript 2 to the power of y end fraction end cell row cell 2 over 8 end cell equals cell fraction numerator k space left parenthesis 0 comma 1 right parenthesis to the power of x space left parenthesis 0 comma 1 right parenthesis to the power of y over denominator k space left parenthesis 0 comma 2 right parenthesis to the power of x space left parenthesis 0 comma 1 right parenthesis to the power of y end fraction end cell row cell 1 fourth end cell equals cell left parenthesis 1 half right parenthesis to the power of x end cell row cell left parenthesis 1 half right parenthesis squared end cell equals cell left parenthesis 1 half right parenthesis to the power of x end cell row x equals 2 end table

 

  • Orde reaksi terhadap open square brackets S to the power of 2 minus sign close square brackets, gunakan data percobaan 2 dan 3


table attributes columnalign right center left columnspacing 0px end attributes row cell v subscript 2 over v subscript 3 end cell equals cell fraction numerator k open square brackets Fe to the power of 3 plus sign close square brackets subscript 2 to the power of x middle dot open square brackets S to the power of 2 minus sign close square brackets 2 to the power of y over denominator k open square brackets Fe to the power of 3 plus sign close square brackets subscript 3 to the power of x middle dot open square brackets S to the power of 2 minus sign close square brackets subscript 3 to the power of y end fraction end cell row cell 8 over 16 end cell equals cell fraction numerator k space left parenthesis 0 comma 2 right parenthesis to the power of x space left parenthesis 0 comma 1 right parenthesis to the power of y over denominator k space left parenthesis 0 comma 2 right parenthesis to the power of x space left parenthesis 0 comma 2 right parenthesis to the power of y end fraction end cell row cell 1 half end cell equals cell left parenthesis 1 half right parenthesis to the power of y end cell row y equals 1 end table


Dengan demikian, rumus laju reaksinya yaitu v double bond k space open square brackets Fe to the power of 3 plus sign close square brackets squared space open square brackets S to the power of 2 minus sign close square brackets.

Jadi, jawaban yang benar adalah C.space​​​​​​​ 

Pembahasan terverifikasi oleh Roboguru

Terakhir diupdate 10 Juni 2021

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