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Dalam suatu gelas kimia 50 mL larutan 0,1 M, kemudian ditambah akuades sebanyak 450 mL. pH larutan berubah dari... menjadi...

Dalam suatu gelas kimia 50 mL larutan begin mathsize 14px style Na O H end style 0,1 M, kemudian ditambah akuades sebanyak 450 mL. pH larutan berubah dari... menjadi...

  1. 12 menjadi 13spacespace

  2. 13 menjadi 14space

  3. 12 menjadi 11space

  4. 13 menjadi 12space

  5. 13 menjadi 11space

Jawaban:

pH begin mathsize 14px style Na O H end style sebelum pengenceran adalah:


begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell open square brackets O H to the power of minus sign close square brackets end cell equals cell n cross times M end cell row blank equals cell 1 cross times 0 comma 1 space M end cell row blank equals cell 10 to the power of negative sign 1 end exponent space M end cell end table end style


begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row pOH equals cell negative sign log space open square brackets O H to the power of minus sign close square brackets end cell row blank equals cell negative sign log space 10 to the power of negative sign 1 end exponent end cell row blank equals 1 row pH equals cell 14 minus sign pOH end cell row blank equals cell 14 minus sign 1 end cell row blank equals 13 end table end style


pH begin mathsize 14px style Na O H end style setelah pengenceran, menggunakan rumus pengenceran:


begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell V subscript 1 cross times M subscript 1 end cell equals cell V subscript 2 cross times M subscript 2 end cell row cell 50 cross times 0 comma 1 end cell equals cell left parenthesis 450 plus 50 right parenthesis cross times M subscript 2 end cell row 5 equals cell 500 cross times M subscript 2 end cell row cell M subscript 2 end cell equals cell begin inline style 5 over 500 end style end cell row blank equals cell 10 to the power of negative sign 2 end exponent space M end cell end table end style


begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row pOH equals cell negative sign log space open square brackets O H to the power of minus sign close square brackets end cell row blank equals cell negative sign log space 10 to the power of negative sign 2 end exponent end cell row blank equals 2 row pH equals cell 14 minus sign pOH end cell row blank equals cell 14 minus sign 2 end cell row blank equals 12 end table end style


Jadi, jawaban yang benar adalah D.

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