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Campuran, 23 gram alkohol begin mathsize 14px style C subscript 2 H subscript 5 O H end style dengan 180 gram air, menghasilkan 200 ml larutan campuran begin mathsize 14px style left parenthesis A subscript r O equals 16 semicolon space C equals 12 semicolon space H equals 1 right parenthesis end style. Tentukanlah:

  1. begin mathsize 14px style X subscript t end style 
  2. begin mathsize 14px style X subscript p end style 
  3. %b/b
  4. bpj/ppm
  5. m
  6. M

Q. 'Ainillana

Master Teacher

Mahasiswa/Alumni Universitas Negeri Yogyakarta

Jawaban terverifikasi

Jawaban

fraksi mol terlarutnya = 0,0476; fraksi mol pelarut = 0,9524: persen massa = 11,33%; bagian per juta = begin mathsize 14px style bottom enclose bold 1 bold comma bold 133 bold cross times bold 10 to the power of bold 5 end enclose end style; molalitas = 2,78 m; molaritas = 2,78 M.

Pembahasan

1. begin mathsize 14px style X subscript t end style = fraksi mol zat terlarut

Fraksi mol merupakan mol bagian, langkah pertama adalah mencari mol zat terlarut dan mol pelarut.

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell n subscript t end cell equals cell massa over M subscript r end cell row blank equals cell fraction numerator 23 space g over denominator 46 space g forward slash mol end fraction end cell row blank equals cell 0 comma 5 space mol end cell row cell n subscript p end cell equals cell massa over M subscript r end cell row blank equals cell 180 over 18 end cell row blank equals cell 10 space mol end cell end table end style 

Maka fraksi mol zat terlarut:

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell X subscript t end cell equals cell fraction numerator n subscript t over denominator n subscript t and n subscript p end fraction end cell row blank equals cell fraction numerator 0 comma 5 over denominator 0 comma 5 plus 10 end fraction end cell row blank equals cell fraction numerator 0 comma 5 over denominator 10 comma 5 end fraction end cell row blank equals cell 0 comma 0476 end cell end table end style 

2. begin mathsize 14px style X subscript p end style = fraksi mol pelarut

fraksi mol pelarut dapat dicari menggunakan rumus:

begin mathsize 14px style X subscript p equals fraction numerator n subscript p over denominator n subscript t and n subscript p end fraction end style 

atau karena di awal sudah diperoleh nilai begin mathsize 14px style X subscript t end style, dapat menggunakan persamaan:

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell X subscript t and X subscript p end cell equals 1 row cell X subscript p end cell equals cell 1 minus sign 0 comma 0476 end cell row blank equals cell 0 comma 9524 end cell end table end style 

3. %b/b = persen massa

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell percent sign b forward slash b end cell equals cell fraction numerator massa space zat space terlarut over denominator massa space larutan end fraction cross times 100 percent sign end cell row blank equals cell fraction numerator 23 space gram over denominator left parenthesis 23 plus 180 right parenthesis gram end fraction cross times 100 percent sign end cell row blank equals cell 11 comma 33 percent sign end cell end table end style 

4. bpj/ppm = bagian per juta

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row bpj equals cell fraction numerator massa space zat space terlarut over denominator massa space larutan end fraction cross times 10 to the power of 6 end cell row blank equals cell fraction numerator 23 space gram over denominator left parenthesis 23 plus 180 right parenthesis space gram end fraction cross times 10 to the power of 6 end cell row blank equals cell 1 comma 133 cross times 10 to the power of 5 space bpj end cell end table end style 

5. m = molalitas: mol tiap kg pelarut

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row m equals cell mol over P end cell row blank equals cell fraction numerator 0 comma 5 space mol over denominator 0 comma 18 space kg end fraction end cell row blank equals cell 2 comma 78 space m end cell end table end style 

6. M = molaritas: mol tiap liter larutan

(anggap massa jenis larutan = 1 g/mL)

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row M equals cell mol over V end cell row blank equals cell fraction numerator 0 comma 5 space mol over denominator 0 comma 18 space L end fraction end cell row blank equals cell 2 comma 78 space M end cell end table end style 

Jadi, fraksi mol terlarutnya = 0,0476; fraksi mol pelarut = 0,9524: persen massa = 11,33%; bagian per juta = begin mathsize 14px style bottom enclose bold 1 bold comma bold 133 bold cross times bold 10 to the power of bold 5 end enclose end style; molalitas = 2,78 m; molaritas = 2,78 M.

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