Roboguru

Berikut terdapat data untuk percobaan dengan reaksi :   Maka persamaan laju reaksinya dapat ditulis sebagai ....

Pertanyaan

Berikut terdapat data untuk percobaan dengan reaksi :


aA space plus bB space rightwards arrow space cC space plus space dD 



Maka persamaan laju reaksinya dapat ditulis sebagai ....space 

  1. v double bond k space open square brackets A close square brackets squared space open square brackets B close square brackets squared  space 

  2. v double bond k space open square brackets A close square brackets  space 

  3. v double bond k space open square brackets B close square brackets  space 

  4. v double bond k space open square brackets A close square brackets space open square brackets B close square brackets  space 

  5. v double bond k space open square brackets A close square brackets space open square brackets B close square brackets squared  space 

Pembahasan Soal:

Secara umum, persamaan laju reaksi dapat dituliskan sebagai berikut.


v double bond k open square brackets pereaksi close square brackets to the power of x  Keterangan colon v double bond laju space reaksi k double bond tetapan space laju space reaksi x double bond orde space reaksi


Untuk menyelesaikan soal diatas, maka perlu dicari terlebih dahulu orde reaksi A dan B.

TIPS! Untuk mencari orde reaksi terhadap A, maka gunakan data percobaan dimana konsentrasi B nya sama, dan begitupun sebaliknya.

  • Orde reaksi A, gunakan percobaan 2 dan 4


table attributes columnalign right center left columnspacing 0px end attributes row v equals cell k space open square brackets A close square brackets to the power of x middle dot open square brackets B close square brackets to the power of y end cell row blank blank blank row cell v subscript 2 over v subscript 4 end cell equals cell fraction numerator k space open square brackets A close square brackets subscript 2 to the power of x middle dot open square brackets B close square brackets subscript 2 to the power of y over denominator k space open square brackets A close square brackets subscript 4 to the power of x middle dot open square brackets B close square brackets subscript 4 to the power of y end fraction end cell row cell fraction numerator 1 comma 0 cross times 10 to the power of negative sign 3 end exponent over denominator 1 comma 0 cross times 10 to the power of negative sign 3 end exponent end fraction end cell equals cell fraction numerator k space left parenthesis 0 comma 1 right parenthesis to the power of x space left parenthesis 0 comma 2 right parenthesis to the power of y over denominator space k space left parenthesis 0 comma 5 right parenthesis to the power of x space left parenthesis 0 comma 2 right parenthesis to the power of y end fraction end cell row 1 equals cell left parenthesis 1 fifth right parenthesis to the power of x end cell row x equals 0 end table

 

  • Orde reaksi terhadap B, gunakan percobaan 1 dan 2


table attributes columnalign right center left columnspacing 0px end attributes row cell v subscript 1 over v subscript 2 end cell equals cell fraction numerator k space open square brackets A close square brackets subscript 1 to the power of x middle dot open square brackets B close square brackets subscript 1 to the power of y over denominator k space open square brackets A close square brackets subscript 2 to the power of x middle dot open square brackets B close square brackets subscript 2 to the power of y end fraction end cell row cell fraction numerator 5 comma 0 cross times 10 to the power of negative sign 4 end exponent over denominator 1 comma 0 cross times 10 to the power of negative sign 3 end exponent end fraction end cell equals cell fraction numerator k space left parenthesis 0 comma 1 right parenthesis to the power of x space left parenthesis 0 comma 1 right parenthesis to the power of y over denominator space k space left parenthesis 0 comma 1 right parenthesis to the power of x space left parenthesis 0 comma 2 right parenthesis to the power of y end fraction end cell row cell fraction numerator 0 comma 5 cross times 10 to the power of negative sign 3 end exponent over denominator 1 comma 0 cross times 10 to the power of negative sign 3 end exponent end fraction end cell equals cell left parenthesis 1 half right parenthesis to the power of y end cell row cell 1 half end cell equals cell left parenthesis 1 half right parenthesis to the power of y end cell row y equals 1 end table


Dengan demikian, persamaan laju reaksinya yaitu v double bond k space open square brackets B close square brackets.

Jadi, jawaban yang benar adalah C.space

Pembahasan terverifikasi oleh Roboguru

Terakhir diupdate 10 Juni 2021

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