Roboguru

Berikut ini tabel kation dan anion:  Rumus kimia yang benar adalah....

Pertanyaan

Berikut ini tabel kation dan anion: 

Rumus kimia yang benar adalah....

Pembahasan Soal:

Rumus senyawa ion ditentukan oleh perbandingan muatan kation dan anionnya. Kation dan anion diberi indeks sedemikian rupa sehingga senyawa bersifat netral.

begin mathsize 14px style X to the power of m plus end exponent plus Y to the power of n minus sign end exponent equals XnYm end style 

begin mathsize 14px style I right parenthesis space K to the power of plus sign space space space space space space space left parenthesis cross times 2 space space space S O subscript 4 to the power of 2 minus sign end exponent space left parenthesis cross times 1 space space space K subscript 2 S O subscript 4 end style 

begin mathsize 14px style I I right parenthesis space space K to the power of plus sign space space space space space space space left parenthesis cross times 3 space space space space space P O subscript 4 to the power of 3 minus sign end exponent space left parenthesis cross times 1 space space space space space K subscript 3 P O subscript 4 end style 

begin mathsize 14px style I I I right parenthesis space Ca to the power of 2 plus sign space left parenthesis cross times 1 space space space space space Cl to the power of minus sign space space space left parenthesis cross times 2 space space space space space Ca Cl subscript 2 end style 

begin mathsize 14px style I V right parenthesis space space Ca to the power of 2 plus sign space space space space space left parenthesis cross times 3 space space space space space space space P O subscript 4 to the power of 3 minus sign end exponent space space space left parenthesis cross times 2 space space space space space space Ca subscript 3 open parentheses P O subscript 4 close parentheses subscript 2 end style  

begin mathsize 14px style V right parenthesis space space Al to the power of 3 plus sign space space space space space left parenthesis cross times 2 space space space space space space S O subscript 4 to the power of 2 minus sign end exponent space left parenthesis cross times 3 space space space space space space Al subscript 2 open parentheses S O subscript 4 close parentheses subscript 3 end style 

Maka rumus senyawa kimiabegin mathsize 14px style I right parenthesis space K subscript 2 S O subscript 4 space space I I right parenthesis space K subscript 3 P O subscript 4 space space I I I right parenthesis space Ca Cl subscript 2 I V right parenthesis space Ca subscript 3 open parentheses P O subscript 4 close parentheses subscript 2 space space space V right parenthesis space space space Al subscript 2 open parentheses S O subscript 4 close parentheses subscript 3 end style  

Pembahasan terverifikasi oleh Roboguru

Terakhir diupdate 13 Maret 2021

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