Berikut data Ksp​ sebagai berikut: CaSO4​SrSO4​BaSO4​PbSO4​​====​2×10−22×10−71×10−102×10−8​  Jika 150 mL larutan yang mengandung ion Ca2+, Sr2+, Ba2+, dan Pb2+ sama yaitu 2×10−4 M, kemudian dicampur dengan 150 mL larutan Na2​SO4​ 2×10−3 M, maka garam sulfat yang mengendap?

Pertanyaan

Berikut data undefined sebagai berikut:

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell Ca S O subscript 4 end cell equals cell 2 cross times 10 to the power of negative sign 2 end exponent end cell row cell Sr S O subscript 4 end cell equals cell 2 cross times 10 to the power of negative sign 7 end exponent end cell row cell Ba S O subscript 4 end cell equals cell 1 cross times 10 to the power of negative sign 10 end exponent end cell row cell Pb S O subscript 4 end cell equals cell 2 cross times 10 to the power of negative sign 8 end exponent end cell end table end style 

Jika 150 mL larutan yang mengandung ion begin mathsize 14px style Ca to the power of 2 plus sign end stylebegin mathsize 14px style Sr to the power of 2 plus sign end stylebegin mathsize 14px style Ba to the power of 2 plus sign end style, dan begin mathsize 14px style Pb to the power of 2 plus sign end style sama yaitu begin mathsize 14px style 2 cross times 10 to the power of negative sign 4 end exponent space M end style, kemudian dicampur dengan 150 mL larutan begin mathsize 14px style Na subscript 2 S O subscript 4 space 2 cross times 10 to the power of negative sign 3 end exponent space M end style, maka garam sulfat yang mengendap?undefined 

S. Hidayati

Master Teacher

Mahasiswa/Alumni Universitas Indonesia

Jawaban terverifikasi

Jawaban

garam sulfat yang mengendap adalah begin mathsize 14px style bottom enclose Ba S O subscript bold 4 end enclose end style dan begin mathsize 14px style bottom enclose Pb S O subscript bold 4 end enclose end style.

Pembahasan

Keempat ion sama-sama bervalensi dua sehingga untuk menghitung undefined, gunakan salah satu ion. 

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell open square brackets Ca to the power of 2 plus sign close square brackets end cell equals cell fraction numerator V cross times M space Ca to the power of 2 plus sign over denominator V space campuran end fraction end cell row blank equals cell fraction numerator 150 space mL cross times 2 cross times 10 to the power of negative sign 4 end exponent space M over denominator left parenthesis 150 plus 150 right parenthesis space mL end fraction end cell row blank equals cell 10 to the power of negative sign 4 end exponent space M end cell end table end style 


begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell left square bracket S O subscript 4 to the power of 2 minus sign end exponent right square bracket end cell equals cell fraction numerator V cross times M space Na subscript 2 S O subscript 4 over denominator V space campuran end fraction end cell row blank equals cell fraction numerator 150 space mL cross times 2 cross times 10 to the power of negative sign 3 end exponent over denominator left parenthesis 150 plus 150 right parenthesis space mL end fraction end cell row blank equals cell 10 to the power of negative sign 3 end exponent space M end cell end table end style 


begin mathsize 14px style Ca S O subscript 4 equilibrium Ca to the power of 2 plus sign and S O subscript 4 to the power of 2 minus sign end exponent end style 

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell Q subscript sp space Ca S O subscript 4 end cell equals cell open square brackets Ca to the power of 2 plus sign close square brackets left square bracket S O subscript 4 to the power of 2 minus sign end exponent right square bracket end cell row blank equals cell left parenthesis 10 to the power of negative sign 4 end exponent right parenthesis left parenthesis 10 to the power of negative sign 3 end exponent right parenthesis end cell row blank equals cell 10 to the power of negative sign 7 end exponent end cell end table end style 


Garam mengendap jika nilai undefined. Di antara keempat garam sulfat, yang memiliki nilai undefined adalah begin mathsize 14px style Ba S O subscript 4 end style dan begin mathsize 14px style Pb S O subscript 4 end style.


Jadi, garam sulfat yang mengendap adalah begin mathsize 14px style bottom enclose Ba S O subscript bold 4 end enclose end style dan begin mathsize 14px style bottom enclose Pb S O subscript bold 4 end enclose end style.

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Jika ion X+ dan Y2− membentuk X2​Y dengan Ksp​=10−7, maka manakah campuran yang dapat menghasilkan endapan: a.  [X+]=10−3+[Y2−]=10−1  b.  [X+]=10−1+[Y2−]=10−3

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