Iklan

Pertanyaan

Berapa pH larutan jika konsentrasi ion H + 0,002 M 0,004 M 0,01 M

Berapa pH larutan jika konsentrasi ion 

  1. 0,002 M
  2. 0,004 M
  3. 0,01 M

Ikuti Tryout SNBT & Menangkan E-Wallet 100rb

Habis dalam

01

:

19

:

35

:

33

Klaim

Iklan

J. Siregar

Master Teacher

Mahasiswa/Alumni Universitas Negeri Medan

Jawaban terverifikasi

Jawaban

pH ketiga larutan berturut-turut adalah .

pH ketiga larutan berturut-turut adalah begin mathsize 14px style 3 minus sign log space 2 semicolon space 3 minus sign log space 4 semicolon space dan space 2 minus sign log space 1 end style

Pembahasan

Penentuan pH larutan dengan menggunakan rumus berikut. Jadi, pH ketiga larutan berturut-turut adalah .

Penentuan pH larutan dengan menggunakan rumus berikut.

begin mathsize 14px style pH equals minus sign log space open square brackets H to the power of plus sign close square brackets end style 

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell 1. space open square brackets H to the power of plus sign close square brackets end cell equals cell 0 comma 002 space M end cell row pH equals cell negative sign log space space open square brackets H to the power of plus sign close square brackets end cell row pH equals cell negative sign log space 0 comma 002 end cell row pH equals cell negative sign log space 2 cross times 10 to the power of negative sign 3 end exponent end cell row pH equals cell 3 minus sign log space 2 end cell row blank blank blank row cell 2. space open square brackets H to the power of plus sign close square brackets end cell equals cell 0 comma 004 space M end cell row pH equals cell negative sign log space space open square brackets H to the power of plus sign close square brackets end cell row pH equals cell negative sign log space 0 comma 004 end cell row pH equals cell negative sign log space 4 cross times 10 to the power of negative sign 3 end exponent end cell row pH equals cell 3 minus sign log space 4 end cell row blank blank blank row cell 3. space open square brackets H to the power of plus sign close square brackets end cell equals cell 0 comma 01 space M end cell row pH equals cell negative sign log space space open square brackets H to the power of plus sign close square brackets end cell row pH equals cell negative sign log space 0 comma 01 end cell row pH equals cell negative sign log space 1 cross times 10 to the power of negative sign 2 end exponent end cell row pH equals cell 2 minus sign log space 1 end cell end table end style

Jadi, pH ketiga larutan berturut-turut adalah begin mathsize 14px style 3 minus sign log space 2 semicolon space 3 minus sign log space 4 semicolon space dan space 2 minus sign log space 1 end style

Perdalam pemahamanmu bersama Master Teacher
di sesi Live Teaching, GRATIS!

8

Iklan

Pertanyaan serupa

Ukurlah pH beberapa air berikut : air leding; air mineral; air suling (distilasi). Berapa pH masing-masing air tersebut? Adakah yang memiliki pH = 7, termasuk air suling? Jika tidak a...

7

5.0

Jawaban terverifikasi

RUANGGURU HQ

Jl. Dr. Saharjo No.161, Manggarai Selatan, Tebet, Kota Jakarta Selatan, Daerah Khusus Ibukota Jakarta 12860

Coba GRATIS Aplikasi Roboguru

Coba GRATIS Aplikasi Ruangguru

Download di Google PlayDownload di AppstoreDownload di App Gallery

Produk Ruangguru

Hubungi Kami

Ruangguru WhatsApp

+62 815-7441-0000

Email info@ruangguru.com

[email protected]

Contact 02130930000

02130930000

Ikuti Kami

©2025 Ruangguru. All Rights Reserved PT. Ruang Raya Indonesia