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Bentuk sederhana dari 6a5×23a2+6a7=....

Pertanyaan

Bentuk sederhana dari 6 a to the power of 5 cross times 2 cubed a squared plus 6 a to the power of 7 equals.... 

D. Rajib

Master Teacher

Mahasiswa/Alumni Universitas Muhammadiyah Malang

Jawaban terverifikasi

Jawaban

diperoleh bentuk sederhana dari bentuk aljabar di atas yaitu 6 a to the power of 5 cross times 2 cubed a squared plus 6 a to the power of 7 equals 54 a to the power of 7.

Pembahasan

Ingat aturan penjumlahan dan perkalian bentuk aljabar berikut.

table attributes columnalign right center left columnspacing 0px end attributes row cell k subscript 1 a plus k subscript 2 a end cell equals cell left parenthesis k subscript 1 plus k subscript 2 right parenthesis a end cell row cell k subscript 1 a cross times k subscript 2 b end cell equals cell k subscript 1 k subscript 2 open parentheses a b close parentheses end cell end table

Ingat juga sifat: a to the power of m cross times a to the power of n equals a to the power of m plus n end exponent

Sehingga diperoleh

table attributes columnalign right center left columnspacing 0px end attributes row cell 6 a to the power of 5 cross times 2 cubed a squared plus 6 a to the power of 7 end cell equals cell open parentheses 6 a to the power of 5 cross times 8 a squared close parentheses plus 6 a to the power of 7 end cell row blank equals cell 48 a to the power of 5 plus 2 end exponent plus 6 a to the power of 7 end cell row blank equals cell 48 a to the power of 7 plus 6 a to the power of 7 end cell row blank equals cell left parenthesis 48 plus 6 right parenthesis a to the power of 7 end cell row blank equals cell 54 a to the power of 7 end cell end table 

Dengan demikian, diperoleh bentuk sederhana dari bentuk aljabar di atas yaitu 6 a to the power of 5 cross times 2 cubed a squared plus 6 a to the power of 7 equals 54 a to the power of 7.

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