Iklan

Pertanyaan

Bentuk sederhana dari ( x z 4 y ​ ) − 3 ÷ ( z 2 y ​ ) − 2 adalah....

Bentuk sederhana dari  adalah ....

  1. begin mathsize 14px style fraction numerator 256 y to the power of 5 over denominator x cubed z to the power of 5 end fraction end style 

  2. begin mathsize 14px style fraction numerator x cubed z to the power of 5 over denominator 256 y to the power of 5 end fraction end style  

  3. begin mathsize 14px style fraction numerator 16 y over denominator x cubed z end fraction end style 

  4. begin mathsize 14px style fraction numerator x cubed z over denominator 16 y end fraction end style 

Ikuti Tryout SNBT & Menangkan E-Wallet 100rb

Habis dalam

00

:

04

:

43

:

01

Klaim

Iklan

N. Ayu

Master Teacher

Mahasiswa/Alumni Universitas Negeri Padang

Jawaban terverifikasi

Jawaban

jawaban yang tepat adalah D.

jawaban yang tepat adalah D.

Pembahasan

Perhatikan perhitungan berikut! Jadi, bentuk sederhana dari adalah . Dengan demikian, jawaban yang tepat adalah D.

Perhatikan perhitungan berikut!

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell open parentheses fraction numerator 4 y over denominator x z end fraction close parentheses to the power of negative 3 end exponent divided by open parentheses fraction numerator 2 y over denominator z end fraction close parentheses to the power of negative 2 end exponent end cell equals cell fraction numerator left parenthesis 4 y right parenthesis to the power of negative 3 end exponent over denominator left parenthesis x z right parenthesis to the power of negative 3 end exponent end fraction divided by fraction numerator left parenthesis 2 y right parenthesis to the power of negative 2 end exponent over denominator z to the power of negative 2 end exponent end fraction end cell row blank equals cell fraction numerator 4 to the power of negative 3 end exponent y to the power of negative 3 end exponent over denominator x to the power of negative 3 end exponent z to the power of negative 3 end exponent end fraction divided by fraction numerator 2 to the power of negative 2 end exponent y to the power of negative 2 end exponent over denominator z to the power of negative 2 end exponent end fraction end cell row blank equals cell fraction numerator x cubed z cubed over denominator 4 cubed y cubed end fraction divided by fraction numerator z squared over denominator 2 squared y squared end fraction end cell row blank equals cell fraction numerator x cubed z cubed over denominator 64 y cubed end fraction divided by fraction numerator z squared over denominator 4 y squared end fraction end cell row blank equals cell fraction numerator x cubed z cubed over denominator 64 y cubed end fraction cross times fraction numerator 4 y squared over denominator z squared end fraction end cell row blank equals cell fraction numerator 4 x cubed z cubed y squared over denominator 64 y cubed z squared end fraction end cell row blank equals cell 1 over 16 x cubed y to the power of 2 minus 3 end exponent z to the power of 3 minus 2 end exponent end cell row blank equals cell 1 over 16 x cubed y to the power of negative 1 end exponent z to the power of 1 end cell row blank equals cell fraction numerator x cubed z over denominator 16 y end fraction end cell end table end style  

Jadi, bentuk sederhana dari begin mathsize 14px style open parentheses fraction numerator 4 y over denominator x z end fraction close parentheses to the power of negative 3 end exponent divided by open parentheses fraction numerator 2 y over denominator z end fraction close parentheses to the power of negative 2 end exponent end style adalah begin mathsize 14px style fraction numerator x cubed z over denominator 16 y end fraction end style.

Dengan demikian, jawaban yang tepat adalah D.

Perdalam pemahamanmu bersama Master Teacher
di sesi Live Teaching, GRATIS!

1

Iklan

Pertanyaan serupa

Hasil dari adalah ....

1

0.0

Jawaban terverifikasi

RUANGGURU HQ

Jl. Dr. Saharjo No.161, Manggarai Selatan, Tebet, Kota Jakarta Selatan, Daerah Khusus Ibukota Jakarta 12860

Coba GRATIS Aplikasi Roboguru

Coba GRATIS Aplikasi Ruangguru

Download di Google PlayDownload di AppstoreDownload di App Gallery

Produk Ruangguru

Hubungi Kami

Ruangguru WhatsApp

+62 815-7441-0000

Email info@ruangguru.com

[email protected]

Contact 02130930000

02130930000

Ikuti Kami

©2026 Ruangguru. All Rights Reserved PT. Ruang Raya Indonesia