Bentuk sederhana dari (p9q−1p5q−5)−2 adalah... .

Pertanyaan

Bentuk sederhana dari $open parentheses fraction numerator p to the power of 5 q to the power of negative 5 end exponent over denominator p to the power of 9 q to the power of negative 1 end exponent end fraction close parentheses to the power of negative 2 end exponent$ adalah... .

N. Puspita

Master Teacher

Jawaban terverifikasi

Jawaban

jawaban yang benar adalah A.

Pembahasan

Dengan menggunakan sifat-sifat bentuk eksponen berikut.

Untuk a comma b element of R , a not equal to 0 , b not equal to 0 , dan m comma n element of R berlaku

bentuk sederhana dari $open parentheses fraction numerator p to the power of 5 q to the power of negative 5 end exponent over denominator p to the power of 9 q to the power of negative 1 end exponent end fraction close parentheses to the power of negative 2 end exponent$ sebagai berikut.

$table attributes columnalign right center left columnspacing 0px end attributes row cell open parentheses fraction numerator p to the power of 5 q to the power of negative 5 end exponent over denominator p to the power of 9 q to the power of negative 1 end exponent end fraction close parentheses to the power of negative 2 end exponent end cell equals cell open parentheses p to the power of 5 q to the power of negative 5 end exponent close parentheses to the power of negative 2 end exponent over open parentheses p to the power of 9 q to the power of negative 1 end exponent close parentheses to the power of negative 2 end exponent space space space space space space space space space space space space space space space Sifat space 1 end cell row blank equals cell fraction numerator open parentheses p to the power of 5 close parentheses to the power of negative 2 end exponent open parentheses q to the power of negative 5 end exponent close parentheses to the power of negative 2 end exponent over denominator open parentheses p to the power of 9 close parentheses to the power of negative 2 end exponent open parentheses q to the power of negative 1 end exponent close parentheses to the power of negative 2 end exponent end fraction space space space space space space space space space Sifat space 2 end cell row blank equals cell fraction numerator p to the power of negative 10 end exponent q to the power of 10 over denominator p to the power of negative 18 end exponent q squared end fraction space space space space space space space space space space space space space space space space space space Sifat space 3 end cell row blank equals cell p to the power of open parentheses negative 10 minus open parentheses negative 18 close parentheses close parentheses end exponent q to the power of 10 minus 2 end exponent space space space space Sifat space 4 end cell row blank equals cell p to the power of open parentheses negative 10 plus 18 close parentheses end exponent q to the power of 8 end cell row blank equals cell p to the power of 8 q to the power of 8 end cell row blank equals cell open parentheses p q close parentheses to the power of 8 space space space space space space space space space space space space space space space space space space space space space space space space end cell end table$

Oleh karena itu, jawaban yang benar adalah A.

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