Bentuk sederhana dari (a−2b4c2)−2(2a−1b−3c−2)−3​ adalah ....

Pertanyaan

Bentuk sederhana dari begin mathsize 14px style open parentheses 2 a to the power of negative 1 end exponent b to the power of negative 3 end exponent c to the power of negative 2 end exponent close parentheses to the power of negative 3 end exponent over open parentheses a to the power of negative 2 end exponent b to the power of 4 c squared close parentheses to the power of negative 2 end exponent end style adalah ....

  1. begin mathsize 14px style fraction numerator a b to the power of 17 over denominator 8 c to the power of 10 end fraction end style 

  2. begin mathsize 14px style fraction numerator a b to the power of 17 over denominator 8 c to the power of 10 end fraction end style 

  3. begin mathsize 14px style fraction numerator 6 a c to the power of 10 over denominator b to the power of 17 end fraction end style 

  4. begin mathsize 14px style fraction numerator 8 a to the power of 10 over denominator b to the power of 12 c squared end fraction end style 

  5. begin mathsize 14px style fraction numerator b to the power of 17 c to the power of 10 over denominator 8 a end fraction end style 

S. Indah

Master Teacher

Mahasiswa/Alumni Universitas Lampung

Jawaban terverifikasi

Jawaban

jawaban yang tepat adalah E.

Pembahasan

Pembahasan

Ingat!

table attributes columnalign right center left columnspacing 0px end attributes row cell a to the power of m cross times a to the power of n end cell equals cell a to the power of m plus n end exponent end cell row cell open parentheses a to the power of m close parentheses to the power of n end cell equals cell a to the power of m cross times n end exponent end cell row cell a to the power of negative n end exponent end cell equals cell 1 over a to the power of n end cell end table

Sehingga,

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell open parentheses 2 a to the power of negative 1 end exponent b to the power of negative 3 end exponent c to the power of negative 2 end exponent close parentheses to the power of negative 3 end exponent over open parentheses a to the power of negative 2 end exponent b to the power of 4 c squared close parentheses to the power of negative 2 end exponent end cell equals cell fraction numerator 2 to the power of negative 3 end exponent a cubed b to the power of 9 c to the power of 6 over denominator a to the power of 4 b to the power of negative 8 end exponent c to the power of negative 4 end exponent end fraction end cell row blank equals cell 2 to the power of negative 3 end exponent a to the power of 3 minus 4 end exponent b to the power of 9 minus left parenthesis negative 8 right parenthesis end exponent c to the power of 6 minus left parenthesis negative 4 right parenthesis end exponent end cell row blank equals cell 2 to the power of negative 3 end exponent a to the power of negative 1 end exponent b to the power of 17 c to the power of 10 end cell row blank equals cell fraction numerator b to the power of 17 c to the power of 10 over denominator 2 cubed a to the power of 1 end fraction end cell row blank equals cell fraction numerator b to the power of 17 c to the power of 10 over denominator 8 a end fraction end cell end table end style 

Oleh karena itu, jawaban yang tepat adalah E.

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