Pertanyaan

Bentuk sederhana adalah .....

Bentuk sederhana begin mathsize 14px style open parentheses fraction numerator 4 space p to the power of negative 1 half end exponent q to the power of 1 half end exponent over denominator 16 space p to the power of 3 over 2 end exponent space q to the power of negative 5 over 2 end exponent end fraction close parentheses to the power of negative 1 end exponent end style adalah .....

  1. begin mathsize 14px style fraction numerator p q cubed over denominator 4 end fraction end style

  2. begin mathsize 14px style fraction numerator 4 p squared over denominator q cubed end fraction end style

  3. begin mathsize 14px style fraction numerator q squared over denominator 4 p end fraction end style

  4. begin mathsize 14px style fraction numerator q cubed over denominator 4 p squared end fraction end style

  5. begin mathsize 14px style fraction numerator q squared over denominator 4 p squared end fraction end style

A. Rizky

Master Teacher

Mahasiswa/Alumni Universitas Negeri Malang

Jawaban terverifikasi

Pembahasan

begin mathsize 14px style open parentheses fraction numerator 4 space p to the power of negative 1 half end exponent q to the power of 1 half end exponent over denominator 16 space p to the power of 3 over 2 end exponent space q to the power of negative 5 over 2 end exponent end fraction close parentheses to the power of negative 1 end exponent equals open parentheses fraction numerator 2 squared space p to the power of negative 1 half end exponent q to the power of 1 half end exponent over denominator 2 to the power of 4 space p to the power of 3 over 2 end exponent space q to the power of negative 5 over 2 end exponent end fraction close parentheses to the power of negative 1 end exponent  space space space space space space space space space space space space space space space space space space space space space space space space space space equals open parentheses 2 to the power of 2 minus 4 end exponent space p to the power of negative 1 half minus 3 over 2 end exponent space q to the power of 1 half minus open parentheses negative 5 over 2 close parentheses end exponent close parentheses to the power of negative 1 end exponent  space space space space space space space space space space space space space space space space space space space space space space space space space space equals open parentheses 2 to the power of negative 2 end exponent space p to the power of negative 2 end exponent space q cubed close parentheses to the power of negative 1 end exponent  space space space space space space space space space space space space space space space space space space space space space space space space space space equals 2 squared space p squared space q to the power of negative 3 end exponent  space space space space space space space space space space space space space space space space space space space space space space space space space space equals fraction numerator 4 space p squared over denominator q cubed end fraction end style

181

4.6 (3 rating)

Dedek Artika

Mudah dimengerti

Iklan

Pertanyaan serupa

Diketahui a  = 0 dan b 0, bentuk sederhana adalah .....

119

0.0

Jawaban terverifikasi

Iklan

RUANGGURU HQ

Jl. Dr. Saharjo No.161, Manggarai Selatan, Tebet, Kota Jakarta Selatan, Daerah Khusus Ibukota Jakarta 12860

Coba GRATIS Aplikasi Roboguru

Coba GRATIS Aplikasi Ruangguru

Download di Google PlayDownload di AppstoreDownload di App Gallery

Produk Ruangguru

Fitur Roboguru

Topik Roboguru

Hubungi Kami

Ruangguru WhatsApp

081578200000

Email info@ruangguru.com

info@ruangguru.com

Contact 02140008000

02140008000

Ikuti Kami

©2022 Ruangguru. All Rights Reserved PT. Ruang Raya Indonesia