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Balok bermassa  diberi  yang membentuk sudut  terh...

Balok bermassa begin mathsize 14px style m equals 1 comma 5 square root of 2 space kg end style diberi begin mathsize 14px style F equals 10 space straight N end style yang membentuk sudut begin mathsize 14px style 45 degree end style terhadap lantai kasar. Apabila balok bergerak dengan percepatan tetap begin mathsize 14px style bevelled 4 over 3 space straight m divided by straight s squared end style koefisien gesekan antara balok dan lantai sebesar ... (begin mathsize 14px style g equals 9 comma 8 space straight m divided by straight s squared end style)undefined 

  1. begin mathsize 14px style 0 comma 2 end style 

  2. begin mathsize 14px style 0 comma 3 end style 

  3. begin mathsize 14px style 0 comma 5 end style 

  4. begin mathsize 14px style 0 comma 4 end style 

  5. begin mathsize 14px style 0 comma 7 end style 

Jawaban:

Diketahui:

begin mathsize 14px style m equals 1 comma 5 space square root of 2 space kg F equals 10 space straight N theta equals 45 degree a equals bevelled 4 over 3 space straight m divided by straight s squared end style 

Ditanyakan:

Koefisien gesek lantai (begin mathsize 14px style mu end style)   ?

Jawab:

Komponen sumbu y

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell capital sigma F subscript y end cell equals 0 row cell N plus F space sin space 45 degree end cell equals w row cell N plus 10 times 1 half square root of 2 end cell equals cell 1 comma 5 square root of 2 times 9 comma 8 end cell row N equals cell 14 comma 7 square root of 2 minus 5 square root of 2 end cell row N equals cell 9 comma 7 square root of 2 space straight N end cell end table end style 

Komponen sumbu x

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell capital sigma F end cell equals cell m times a end cell row cell F space cos space 45 degree minus mu times N end cell equals cell m times a end cell row cell 10 times 1 half square root of 2 minus mu times 9 comma 7 square root of 2 end cell equals cell 1 comma 5 square root of 2 times 4 over 3 end cell row cell 5 square root of 2 minus mu times 9 comma 7 square root of 2 end cell equals cell 2 square root of 2 end cell row cell 9 comma 7 times mu end cell equals cell 5 minus 2 end cell row mu equals cell fraction numerator 3 over denominator 9 comma 7 end fraction end cell row mu equals cell 0 comma 3 end cell end table end style 

Maka koefisien gesek lantai adalah sebesar 0,3.

Jadi, jawaban yang benar adalah B.undefined

0

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