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P e n ye l es aian d a r i s i s t e m p ers amaan y = 4 x 2 − 2 x d an g a r i s 2 x − 2 1 ​ y − 1 = 0 a d a l ah …

  1. left parenthesis 1 comma 0 right parenthesis space d a n space left parenthesis 1 comma 2 right parenthesis

  2. open parentheses 0 comma 1 fourth close parentheses space d a n space left parenthesis 1 comma 2 right parenthesis

  3. open parentheses 0 comma 1 half close parentheses space d a n space left parenthesis 1 comma 2 right parenthesis

  4. open parentheses 1 half comma 0 close parentheses space d a n space left parenthesis 1 comma 2 right parenthesis

  5. open parentheses 1 fourth comma 0 close parentheses space d a n space left parenthesis 1 comma 2 right parenthesis

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L. Indah

Master Teacher

Mahasiswa/Alumni Universitas Siliwangi

Jawaban terverifikasi

Pembahasan

bottom enclose 2 x minus 1 half y minus 1 equals 0 space end enclose subscript open parentheses cross times 2 close parentheses end subscript 4 x minus y minus 2 equals 0 left right arrow y equals 4 x minus 2 S u b t i t u s i k a n space y equals 4 x minus 2 space k e space p e r s a m a a n y equals 4 x squared minus 2 x comma space m a k a space d i p e r o l e h colon 4 x squared minus 2 x equals 4 x minus 2 4 x squared minus 2 x minus 4 x plus 2 equals 0 bottom enclose 4 x squared minus 6 x plus 2 equals 0 end enclose open parentheses cross times 1 half close parentheses space 2 x squared minus 3 x plus 1 equals 0 open parentheses 2 x minus 1 close parentheses open parentheses x minus 1 close parentheses equals 0 D i d a p a t space x equals 1 half space d a n space x equals 1 comma space s e l a n j u t n y a s u b s t i t u s i k a n space k e space p e r s a m a a n space y equals 4 x minus 2 comma m a k a space d i p e r o l e h colon x equals 1 half rightwards double arrow y equals 4 open parentheses 1 half close parentheses minus 2 equals 2 minus 2 equals 0 x equals 1 rightwards double arrow y equals 4 left parenthesis 1 right parenthesis minus 2 equals 4 minus 2 equals 2 J a d i comma space p e n y e l e s a i a n n y a space a d a l a h colon open parentheses 1 half comma 0 close parentheses space d a n space left parenthesis 1 comma 2 right parenthesis.

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Penyelesaian dari sistem persamaan y = x 2 − 4 x − 24 d an 2 x − y + 3 = 0 adalah…

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