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integral open curly brackets cos squared invisible function application open parentheses 2 x minus 1 close parentheses minus sin squared invisible function application open parentheses 2 x minus 1 close parentheses close curly brackets d x equals horizontal ellipsis

  1. cos invisible function application open parentheses 4 x minus 2 close parentheses plus c

  2. 1 fourth cos invisible function application open parentheses 4 x minus 2 close parentheses plus c

  3. 1 fourth sin invisible function application open parentheses 4 x minus 2 close parentheses plus c

  4. negative 1 fourth sin invisible function application open parentheses 4 x minus 2 close parentheses plus c

  5. negative 1 half sin invisible function application open parentheses 4 x minus 2 close parentheses plus c

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A. Acfreelance

Master Teacher

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Soal diubah dengan rumus

Soal diubah dengan rumus cos squared invisible function application x minus sin squared invisible function application x equals cos invisible function application 2 x

equals integral cos invisible function application 2 left parenthesis 2 x minus 1 right parenthesis d x equals integral cos invisible function application left parenthesis 4 x minus 2 right parenthesis d x equals 1 fourth sin invisible function application left parenthesis 4 x minus 2 right parenthesis plus c

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