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Pertanyaan

integral cos invisible function application x. cos invisible function application open parentheses sin invisible function application x close parentheses d x equals horizontal ellipsis 

  1. cos invisible function application open parentheses cos invisible function application x close parentheses plus C 

  2. sin invisible function application open parentheses sin invisible function application x close parentheses plus C 

  3. cos invisible function application open parentheses sin invisible function application x close parentheses plus C 

  4. sin invisible function application open parentheses cos invisible function application x close parentheses plus C  

  5. negative sin invisible function application open parentheses sin invisible function application x close parentheses plus C 

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F. Kurnia

Master Teacher

Mahasiswa/Alumni Universitas Jember

Jawaban terverifikasi

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Pembahasan

Gunakan integral subtitusi : Jadi,

Gunakan integral subtitusi :

u equals sin invisible function application x fraction numerator d u over denominator d x end fraction equals cos invisible function application x d x equals fraction numerator d u over denominator cos invisible function application x end fraction 

Jadi,

integral cos invisible function application x. cos invisible function application open parentheses sin invisible function application x close parentheses d x integral cos invisible function application x. cos invisible function application open parentheses u close parentheses fraction numerator d u over denominator cos invisible function application x end fraction equals integral cos invisible function application u d u equals sin invisible function application u plus C equals sin invisible function application open parentheses sin invisible function application x close parentheses plus C  

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