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Pertanyaan

x → 2 lim ​ ( x − 2 ) tan ( 3 x − 6 ) 1 − cos 2 ( x − 2 ) ​ = ....

 

  1. begin mathsize 14px style 1 over 6 end style 

  2. begin mathsize 14px style 1 third end style 

  3. begin mathsize 14px style 1 half end style 

  4. begin mathsize 14px style 1 end style 

  5. begin mathsize 14px style 2 end style 

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P. Anggrayni

Master Teacher

Jawaban terverifikasi

Jawaban

jawaban yang tepat adalah B.

jawaban yang tepat adalah B.space space  

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Pembahasan

Misal sehingga jika maka . Diperoleh Jadi, jawaban yang tepat adalah B.

Misal begin mathsize 14px style straight y equals straight x minus 2 end style sehingga jika begin mathsize 14px style straight x rightwards arrow 2 end style maka begin mathsize 14px style straight y rightwards arrow 0 end style. Diperoleh 

begin mathsize 14px style space limit as straight x rightwards arrow 2 of space fraction numerator 1 minus cos squared left parenthesis straight x minus 2 right parenthesis over denominator left parenthesis straight x minus 2 right parenthesis space tan left parenthesis 3 straight x minus 6 right parenthesis end fraction equals limit as straight x rightwards arrow 2 of fraction numerator 1 minus cos squared open parentheses straight x minus 2 close parentheses over denominator left parenthesis straight x minus 2 right parenthesis space tan left parenthesis 3 left parenthesis straight x minus 2 right parenthesis right parenthesis end fraction equals limit as straight y rightwards arrow 0 of fraction numerator sin squared left parenthesis straight y right parenthesis over denominator straight y space tan space left parenthesis 3 straight y right parenthesis end fraction equals limit as straight y rightwards arrow 0 of fraction numerator sin left parenthesis straight y right parenthesis over denominator straight y end fraction space. space limit as straight y rightwards arrow 0 of fraction numerator sin space left parenthesis straight y right parenthesis over denominator sin space left parenthesis 3 straight y right parenthesis end fraction equals space 1 space. space 1 third space equals space 1 third end style    

Jadi, jawaban yang tepat adalah B.space space  

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x → 0 lim ​ tan ( 2 x ) − tan ( x ) sin ( 2 x ) − sin ( x ) ​ = ....

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