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Pertanyaan

x → 0 lim ​ 3 x 2 cos ( x ) sin ( 4 x ) + sin ( 2 x ) ​ = ....

 

  1. begin mathsize 14px style 1 fourth end style 

  2. begin mathsize 14px style 1 half end style 

  3. begin mathsize 14px style 1 end style 

  4. begin mathsize 14px style 3 over 2 end style 

  5. begin mathsize 14px style 2 end style 

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P. Anggrayni

Master Teacher

Jawaban terverifikasi

Jawaban

jawaban yang tepat adalah E.

jawaban yang tepat adalah E.space space  

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Pembahasan

Jadi, jawaban yang tepat adalah E.

begin mathsize 14px style limit as straight x rightwards arrow 0 of fraction numerator sin left parenthesis 4 straight x right parenthesis plus sin left parenthesis 2 straight x right parenthesis over denominator 3 straight x squared cos left parenthesis straight x right parenthesis end fraction equals limit as straight x rightwards arrow 0 of fraction numerator 2 sin left parenthesis begin display style fraction numerator 4 straight x plus 2 straight x over denominator 2 end fraction end style right parenthesis space sin left parenthesis begin display style fraction numerator 4 straight x minus 2 straight x over denominator 2 end fraction end style right parenthesis over denominator 3 straight x squared cos left parenthesis straight x right parenthesis end fraction equals limit as straight x rightwards arrow 0 of fraction numerator 2 sin left parenthesis 3 straight x right parenthesis space sin left parenthesis straight x right parenthesis over denominator 3 straight x squared cos left parenthesis straight x right parenthesis end fraction equals 2 over 3 space. space limit as straight x rightwards arrow 0 of fraction numerator sin begin display style left parenthesis end style begin display style 3 end style begin display style straight x end style begin display style right parenthesis end style over denominator straight x end fraction space. space limit as straight x rightwards arrow 0 of fraction numerator tan begin display style left parenthesis end style begin display style straight x end style begin display style right parenthesis end style over denominator straight x end fraction equals 2 over 3. space 3 space. space 1 equals 2 end style 

Jadi, jawaban yang tepat adalah E.space space  

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Afifi Indi Ramadhani

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x → 0 lim ​ tan ( 2 x ) − tan ( x ) sin ( 2 x ) − sin ( x ) ​ = ....

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