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Pertanyaan

integral subscript 1 superscript 4 5 x squared minus 6 square root of x plus 2 over x squared d x

Pembahasan Soal:

ingat!

 table attributes columnalign right center left columnspacing 0px end attributes row cell integral subscript straight a superscript straight b mx to the power of straight n space dx end cell equals cell fraction numerator straight m over denominator straight n plus 1 end fraction straight x to the power of straight n plus 1 end exponent vertical line subscript straight a superscript straight b end cell row blank equals cell fraction numerator straight m over denominator straight n plus 1 end fraction straight b to the power of straight n plus 1 end exponent minus fraction numerator straight m over denominator straight n plus 1 end fraction straight a to the power of straight n plus 1 end exponent end cell end table

table attributes columnalign right center left columnspacing 0px end attributes row blank blank cell integral subscript 1 superscript 4 5 x squared minus 6 square root of x plus 2 over x squared d x end cell row blank equals cell integral subscript 1 superscript 4 5 x squared minus 6 x to the power of 1 half end exponent plus 2 x to the power of negative 2 end exponent space d x end cell row blank equals cell open square brackets 5 over 3 x cubed minus fraction numerator 6 over denominator begin display style 3 over 2 end style end fraction x to the power of 3 over 2 end exponent plus fraction numerator 2 over denominator negative 1 end fraction x to the power of negative 1 end exponent close square brackets subscript 1 superscript 4 end cell row blank equals cell open square brackets 5 over 3 left parenthesis 4 right parenthesis cubed minus 4 left parenthesis 4 right parenthesis to the power of 3 over 2 end exponent minus 2 left parenthesis 4 right parenthesis to the power of negative 1 end exponent close square brackets minus open square brackets 5 over 3 left parenthesis 1 right parenthesis cubed minus 4 left parenthesis 1 right parenthesis to the power of 3 over 2 end exponent minus 2 left parenthesis 1 right parenthesis to the power of negative 1 end exponent close square brackets end cell row blank equals cell open square brackets 445 over 6 close square brackets minus open square brackets negative 13 over 3 close square brackets end cell row blank equals cell 157 over 2 end cell end table

Pembahasan terverifikasi oleh Roboguru

Dijawab oleh:

O. Rahmawati

Mahasiswa/Alumni UIN Sunan Gunung Djati Bandung

Terakhir diupdate 07 Juni 2021

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Pembahasan Soal:

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Pembahasan Soal:

integral subscript negative 2 end subscript superscript 1 2 x minus 4 space d x equals x squared minus 4 x right enclose blank end enclose subscript negative 2 end subscript superscript 1 equals space left parenthesis 1 right parenthesis squared minus 4 left parenthesis 1 right parenthesis squared minus left parenthesis negative 2 right parenthesis squared plus 4 left parenthesis negative 2 right parenthesis  space space space space space space space space space space space space space space space space space space space space space space space space equals 1 minus space 16 equals negative 15

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Nilai dari adalah ...

Pembahasan Soal:

integral subscript a superscript b a x to the power of n d x equals open square brackets fraction numerator a over denominator n plus 1 end fraction x to the power of n plus 1 end exponent close square brackets subscript a to the power of b equals left parenthesis fraction numerator a over denominator n plus 1 end fraction b to the power of n plus 1 end exponent right parenthesis minus left parenthesis fraction numerator a over denominator n plus 1 end fraction a to the power of n plus 1 end exponent right parenthesis    integral subscript negative 1 end subscript superscript 2 left parenthesis 3 x squared minus 2 x plus 1 right parenthesis d x equals open square brackets x cubed minus x squared plus x close square brackets subscript negative 1 end subscript squared    equals left parenthesis left parenthesis 2 right parenthesis cubed minus left parenthesis 2 right parenthesis squared plus left parenthesis 2 right parenthesis right parenthesis minus left parenthesis left parenthesis 1 minus 1 right parenthesis squared plus left parenthesis negative 1 right parenthesis right parenthesis  equals left parenthesis 6 right parenthesis minus left parenthesis negative 3 right parenthesis  equals 9

0

Roboguru

Jika , maka nilai  ...

Pembahasan Soal:

table attributes columnalign right center left columnspacing 0px end attributes row cell integral subscript 0 superscript 2 open parentheses open parentheses m plus 1 close parentheses x squared plus 2 m x plus 3 close parentheses straight d x end cell equals 54 row cell open square brackets fraction numerator open parentheses m plus 1 close parentheses over denominator 3 end fraction x cubed plus fraction numerator up diagonal strike 2 m over denominator up diagonal strike 2 end fraction x squared plus 3 x plus C close square brackets subscript 0 superscript 2 end cell equals 54 row cell open parentheses fraction numerator open parentheses m plus 1 close parentheses over denominator 3 end fraction open parentheses 2 close parentheses cubed plus m open parentheses 2 close parentheses squared plus 3 open parentheses 2 close parentheses plus C close parentheses minus open parentheses 0 plus C close parentheses end cell equals 54 row cell fraction numerator 8 open parentheses m plus 1 close parentheses over denominator 3 end fraction plus 4 m plus 6 end cell equals 54 row cell fraction numerator 8 m plus 8 over denominator 3 end fraction plus 4 m plus 6 end cell equals 54 row cell fraction numerator 8 m plus 8 plus 12 m plus 18 over denominator 3 end fraction end cell equals 54 row cell 20 m plus 26 end cell equals 54 row cell 20 m end cell equals cell 54 minus 26 end cell row cell 20 m end cell equals 28 row m equals cell 28 over 20 end cell row m equals cell 7 over 5 end cell end table 

Nilai 10 m:

table attributes columnalign right center left columnspacing 0px end attributes row cell 10 m end cell equals cell 10 open parentheses 7 over 5 close parentheses end cell row blank equals cell 70 over 5 end cell row blank equals 14 end table

Sehingga, nilai 10 m adalah 14.

Jadi, tidak ada pilihan jawaban yang tepat.

0

Roboguru

Hasil = ....

Pembahasan Soal:

begin mathsize 14px style integral from negative 1 to 2 of open parentheses x cubed plus 3 x squared plus 4 x plus 5 close parentheses space d x equals open square brackets 1 fourth x to the power of 4 plus 3 over 3 x cubed plus 4 over 2 x squared plus 5 x close square brackets subscript negative 1 end subscript superscript 2  equals open square brackets 1 fourth x to the power of 4 plus x cubed plus 2 x squared plus 5 x close square brackets subscript negative 1 end subscript superscript 2  equals open curly brackets 1 fourth open parentheses 2 close parentheses to the power of 4 plus open parentheses 2 close parentheses cubed plus 2 open parentheses 2 close parentheses squared plus 5 open parentheses 2 close parentheses close curly brackets minus open curly brackets 1 fourth open parentheses negative 1 close parentheses to the power of 4 plus open parentheses negative 1 close parentheses cubed plus 2 open parentheses negative 1 close parentheses squared plus 5 open parentheses negative 1 close parentheses close curly brackets  equals open parentheses 4 plus 8 plus 8 plus 10 close parentheses minus open parentheses 1 fourth minus 1 plus 2 minus 5 close parentheses  equals 30 minus open parentheses negative 15 over 4 close parentheses  equals fraction numerator 120 plus 15 over denominator 4 end fraction  equals 135 over 4 equals 33 3 over 4 end style

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