Pertanyaan

x → + ∞ lim 3 5 + 8 x 6 6 + x 2 = ....

$x \to + \infty lim \frac{6 6 + x ^{2}}{3 5 + 8 x} = ....$

-1
0
1

Ikuti Tryout SNBT & Menangkan E-Wallet 100rb

Habis dalam

Klaim

I. Roy

Master Teacher

Mahasiswa/Alumni Universitas Negeri Surabaya

Jawaban terverifikasi

Pembahasan

$limit as x rightwards arrow plus infinity of open parentheses fraction numerator root index 6 of 6 plus x squared end root over denominator cube root of 5 plus 8 x end root end fraction close parentheses open parentheses fraction numerator begin display style fraction numerator 1 over denominator cube root of x end fraction end style over denominator begin display style fraction numerator 1 over denominator cube root of x end fraction end style end fraction close parentheses equals limit as x rightwards arrow plus infinity of open parentheses fraction numerator root index 6 of begin display style 6 over x squared end style plus begin display style x squared over x squared end style end root over denominator cube root of begin display style 5 over x end style plus begin display style fraction numerator 8 x over denominator x end fraction end style end root end fraction close parentheses equals fraction numerator root index 6 of 0 plus 1 end root over denominator cube root of 0 plus 8 end root end fraction equals 1 half$

Perdalam pemahamanmu bersama Master Teacher
di sesi Live Teaching, GRATIS!

4.8 (5 rating)

Ilma erli

Makasih ❤️

Intan Dyah Rahmawati

Bantu banget Makasih ❤️

Pertanyaan serupa

Nilai dari L i m x → ∞ ( 7 x − 3 − 7 x + 1 ) =

4.2

Jawaban terverifikasi

$\style{font-size:14px}{\mathrm{Nilai}}\style{font-size:14px}\;\underset{\style{font-size:14px}{\mathrm x}\style{font-size:14px}\rightarrow\style{font-size:14px}\infty}{\style{font-size:14px}\lim}\left(\sqrt{\style{font-size:14px}4\style{font-size:14px}{\mathrm x}^\style{font-size:14px}2\style{font-size:14px}\;\style{font-size:14px}+\style{font-size:14px}\;\style{font-size:14px}3\style{font-size:14px}{\mathrm x}\style{font-size:14px}\;\style{font-size:14px}+\style{font-size:14px}\;\style{font-size:14px}4}\style{font-size:14px}\;\style{font-size:14px}-\style{font-size:14px}\;\style{font-size:14px}2\style{font-size:14px}{\mathrm x}\style{font-size:14px}\;\style{font-size:14px}+\style{font-size:14px}1\right)\style{font-size:14px}\;\style{font-size:14px}=\style{font-size:14px}\;\style{font-size:14px}.\style{font-size:14px}.\style{font-size:14px}.\style{font-size:14px}.$

4.3

Jawaban terverifikasi

Nilai dari x → ∞ lim ( 4 x 2 − 8 x + 6 − 4 x 2 + 16 x − 3 ) = .....

4.8

Jawaban terverifikasi

Nilai dari x → ∞ lim ( 81 x 2 − 10 x + 15 − 9 x + 1 ) = ....

4.5

Jawaban terverifikasi

Nilai dari x → ∞ lim x + x + x x = ...

4.2

Jawaban terverifikasi