Pertanyaan

∫ x − 2 x 2 − 16 d x = …

$\int \frac{x ^{2} - 16}{x - 2} d x = \dots$

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Habis dalam

Klaim

N. Ayu

Master Teacher

Mahasiswa/Alumni Universitas Negeri Padang

Jawaban terverifikasi

Pembahasan

$integral fraction numerator x squared minus 16 over denominator square root of x minus 2 end fraction d x equals integral fraction numerator open parentheses x minus 4 close parentheses open parentheses x plus 4 close parentheses over denominator square root of x minus 2 end fraction d x equals integral fraction numerator open parentheses square root of x plus 2 close parentheses open parentheses square root of x minus 2 close parentheses open parentheses x plus 4 close parentheses over denominator square root of x minus 2 end fraction d x equals integral open parentheses square root of x plus 2 close parentheses open parentheses x plus 4 close parentheses d x equals integral open parentheses x square root of x plus 4 square root of x plus 2 x plus 8 close parentheses d x equals integral open parentheses x to the power of 3 over 2 end exponent plus 4 x to the power of 1 half end exponent plus 2 x plus 8 close parentheses d x equals 2 over 5 x to the power of 5 over 2 end exponent plus 4.2 over 3 x to the power of 3 over 2 end exponent plus 2 over 2 x squared plus 8 x plus C equals 2 over 5 x squared. x to the power of 1 half end exponent plus 8 over 3 x. x to the power of 1 half end exponent plus x squared plus 8 x plus C equals 2 over 5 x squared. x to the power of 1 half end exponent plus 8 over 3 x. x to the power of 1 half end exponent plus x squared plus 8 x plus C equals 2 over 5 x to the power of 5 over 2 end exponent plus 4.2 over 3 x to the power of 3 over 2 end exponent plus 2 over 2 x squared plus 8 x plus C equals 2 over 5 x squared. x to the power of 1 half end exponent plus 8 over 3 x. x to the power of 1 half end exponent plus x squared plus 8 x plus C equals x open parentheses 2 over 5 x. x to the power of 1 half end exponent plus 8 over 3 x to the power of 1 half end exponent plus x plus 8 close parentheses plus C equals x open parentheses 2 over 5 x square root of x plus 8 over 3 square root of x plus x plus 8 close parentheses plus C$