Iklan

Pertanyaan

x → 3 lim ​ x + 1 ​ − 7 − x ​ x 2 − 9 ​ = ....

  1. 8

  2. 12

  3. 16

  4. 20

  5. 24

Ikuti Tryout SNBT & Menangkan E-Wallet 100rb

Habis dalam

01

:

11

:

27

:

01

Klaim

Iklan

D. Kamilia

Master Teacher

Mahasiswa/Alumni Universitas Negeri Malang

Jawaban terverifikasi

Pembahasan

table attributes columnalign right center left columnspacing 0px end attributes row cell limit as x rightwards arrow 3 of invisible function application fraction numerator x squared minus 9 over denominator square root of x plus 1 end root minus square root of 7 minus x end root end fraction end cell equals cell limit as x rightwards arrow 3 of invisible function application fraction numerator x squared minus 9 over denominator square root of x plus 1 end root minus square root of 7 minus x end root end fraction. fraction numerator square root of x plus 1 end root plus square root of 7 minus x end root over denominator square root of x plus 1 end root plus square root of 7 minus x end root end fraction end cell row blank equals cell limit as x rightwards arrow 3 of invisible function application fraction numerator open parentheses x squared minus 9 close parentheses open parentheses square root of x plus 1 end root plus square root of 7 minus x end root close parentheses over denominator open parentheses square root of x plus 1 end root close parentheses squared minus open parentheses square root of 7 minus x end root close parentheses squared end fraction end cell row blank equals cell limit as x rightwards arrow 3 of invisible function application fraction numerator open parentheses x squared minus 9 close parentheses open parentheses square root of x plus 1 end root plus square root of 7 minus x end root close parentheses over denominator open parentheses x plus 1 close parentheses minus open parentheses 7 minus x close parentheses end fraction end cell row blank equals cell limit as x rightwards arrow 3 of invisible function application fraction numerator open parentheses x squared minus 9 close parentheses open parentheses square root of x plus 1 end root plus square root of 7 minus x end root close parentheses over denominator 2 x minus 6 end fraction end cell row blank equals cell limit as x rightwards arrow 3 of invisible function application fraction numerator open parentheses x minus 3 close parentheses open parentheses x plus 3 close parentheses open parentheses square root of x plus 1 end root plus square root of 7 minus x end root close parentheses over denominator 2 open parentheses x minus 3 close parentheses end fraction end cell row blank equals cell limit as x rightwards arrow 3 of invisible function application fraction numerator open parentheses x plus 3 close parentheses open parentheses square root of x plus 1 end root plus square root of 7 minus x end root close parentheses over denominator 2 end fraction end cell row blank equals cell fraction numerator open parentheses 3 plus 3 close parentheses open parentheses square root of 3 plus 1 end root plus square root of 7 minus 3 end root close parentheses over denominator 2 end fraction end cell row blank equals cell fraction numerator 6 open parentheses square root of 4 plus square root of 4 close parentheses over denominator 2 end fraction end cell row blank equals cell 24 over 2 end cell row blank equals cell box enclose 12 end cell end table

Perdalam pemahamanmu bersama Master Teacher
di sesi Live Teaching, GRATIS!

2

greenaa afrina

Pembahasan lengkap banget

Alyssa Noverita Putri

Ini yang aku cari! Bantu banget Mudah dimengerti Pembahasan lengkap banget Makasih ❤️

Rizki Adhitia Saputri

Makasih ❤️

Iklan

Pertanyaan serupa

Tentukan nilai dari x → − 2 lim ​ x + 2 2 x + 13 ​ − x + 11 ​ ​ .

1

4.7

Jawaban terverifikasi

RUANGGURU HQ

Jl. Dr. Saharjo No.161, Manggarai Selatan, Tebet, Kota Jakarta Selatan, Daerah Khusus Ibukota Jakarta 12860

Coba GRATIS Aplikasi Roboguru

Coba GRATIS Aplikasi Ruangguru

Download di Google PlayDownload di AppstoreDownload di App Gallery

Produk Ruangguru

Hubungi Kami

Ruangguru WhatsApp

+62 815-7441-0000

Email info@ruangguru.com

[email protected]

Contact 02130930000

02130930000

Ikuti Kami

©2025 Ruangguru. All Rights Reserved PT. Ruang Raya Indonesia