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V o l u m e b e n d a p u t a r d a r i d a er ah y an g d iba t a s i o l e h k u r v a y = 3 x d an y = x 2 y an g d i p u t a r m e n g e l i l in g i s u mb u X se ja u h 36 0 ∘ a d a l ah ....

  1. 62 over 5 straight pi space satuan space volume

  2. 63 over 3 straight pi space satuan space volume

  3. 162 over 5 straight pi space satuan space volume

  4. 98 over 3 straight pi space satuan space volume

  5. 262 over 5 straight pi space satuan space volume

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F. Pratama

Master Teacher

Mahasiswa/Alumni Universitas Putra Indonesia YPTK Padang

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P e r t a m a minus t a m a space c a r i space t i t i k space p o t o n g space a n t a r a space g a r i s space d a n space k u r v a space  y equals y  x squared equals 3 x  x squared minus 3 x equals 0  x left parenthesis x minus 3 right parenthesis equals 0  x equals 0 space a t a u space x equals 3    M a k a space v o l u m e space d a e r a h space t e r s e b u t space a d a l a h  straight pi integral subscript 0 superscript 3 left parenthesis left parenthesis 3 straight x right parenthesis squared minus left parenthesis straight x squared right parenthesis squared right parenthesis space dx  straight pi integral subscript 0 superscript 3 left parenthesis 9 straight x squared minus left parenthesis straight x to the power of 4 right parenthesis space dx  right enclose straight pi integral subscript 0 superscript 3 open parentheses 3 straight x cubed minus 1 fifth straight x to the power of 5 space close parentheses space end enclose subscript 0 superscript 3 equals straight pi open parentheses 81 minus 242 over 5 close parentheses equals 162 over 5 straight pi space satuan space volume

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Volume benda putar yang terjadi bila daerah yang dibatasi oleh kurva y = 4 − x 2 dan garis y = x + 2 diputar mengelilingi sumbu X sejauh 36 0 ∘ adalah....

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