Pertanyaan

Nilai dari x → ∞ lim ( 4 x 2 − 8 x + 3 − 2 x − 4 ) = ....

$Nilai dari x \to \infty lim (4 x^{2} - 8 x + 3 - 2 x - 4) = ....$

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F. Pratama

Master Teacher

Mahasiswa/Alumni Universitas Putra Indonesia YPTK Padang

Jawaban terverifikasi

Pembahasan

$I n g a t space r u m u s limit as x rightwards arrow infinity of open parentheses square root of a x squared plus b x plus c end root space minus space square root of a x squared plus q x plus r end root close parentheses space equals space fraction numerator b minus q over denominator 2 square root of a end fraction limit as x rightwards arrow infinity of open parentheses square root of 4 x squared minus 8 x plus 3 end root minus square root of left parenthesis 2 x plus 4 right parenthesis squared end root close parentheses limit as x rightwards arrow infinity of open parentheses square root of 4 x squared minus 8 x plus 3 end root space minus space square root of 4 x squared plus 16 x plus 16 end root close parentheses space equals space fraction numerator negative 8 minus 16 over denominator 2 square root of 4 end fraction equals negative 24 over 4 equals negative 6$

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$\style{font-size:14px}{\mathrm{Nilai}}\style{font-size:14px}\;\underset{\style{font-size:14px}{\mathrm x}\style{font-size:14px}\rightarrow\style{font-size:14px}\infty}{\style{font-size:14px}\lim}\left(\sqrt{\style{font-size:14px}4\style{font-size:14px}{\mathrm x}^\style{font-size:14px}2\style{font-size:14px}\;\style{font-size:14px}+\style{font-size:14px}\;\style{font-size:14px}3\style{font-size:14px}{\mathrm x}\style{font-size:14px}\;\style{font-size:14px}+\style{font-size:14px}\;\style{font-size:14px}4}\style{font-size:14px}\;\style{font-size:14px}-\style{font-size:14px}\;\style{font-size:14px}2\style{font-size:14px}{\mathrm x}\style{font-size:14px}\;\style{font-size:14px}+\style{font-size:14px}1\right)\style{font-size:14px}\;\style{font-size:14px}=\style{font-size:14px}\;\style{font-size:14px}.\style{font-size:14px}.\style{font-size:14px}.\style{font-size:14px}.$

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