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Ke d a l am 100 m L l a r u tan C a C r O 4 ​ 0 , 4 M d i t ambahkan 100 m L l a r u tan A g N O 3 ​ 0 , 4 M , jika Ks p A g 2 ​ C r O 4 ​ = 9 x 1 0 − 12 , ma ss a z a t y an g m e n g e n d a p a d a l ah .... ( A r : O = 16 , C a = 40 , C r = 52 , A g = 108 , N = 14 )

  1. 3,32 gram

     

  2. 6,64 gram

  3. 13,28 gram

  4. 16,60 gram

  5. 33,20 gram

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D. Ayu

Master Teacher

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space space space space space space space C a C r O subscript 4 space space space space space space space space space space space space plus space space space space space space 2 A g N O subscript 3 rightwards arrow space space space space space space space space space space space space A g subscript 2 C r O subscript 4 plus C a left parenthesis N O subscript 3 right parenthesis subscript 2  M equals 0 comma 4 M x 100 m L space space space space space space space space space space space 0 comma 4 M x 100 m L space space space space space space space space space space minus space space space space space space space space space space space space space space space space minus  space space space space equals 40 m m o l space space space space space space space space space space space space space space space space space space space space equals 40 m m o l  bottom enclose R space equals 20 m m o l space space space space space space space space space space space space space space space space space space space space space space space space 40 m m o l space space space space space space space space space space space space 20 m m o l space space space space space space space space space 20 m m o l end enclose  S equals 20 m m o l space space space space space space space space space space space space space space space space space space space space space space space space space minus space space space space space space space space space space space space space space space space space space space space space space space 20 m m o l space space space space space space space space space 20 m m o l  K a r e n a space d i k e t a h u i space K s p space A g subscript 2 C r O subscript 4 comma space m a k a space m a s s a space y a n g space m e n g e n d a p space k e m u n g k i n a n space b e s a r space a d a l a h space A g subscript 2 C r O subscript 4. space M m o l space s i s a space u n t u k space A g subscript 2 C r O subscript 4 space a d a l a h space 20 m m o l.  M o l space A g subscript 2 C r O subscript 4 equals fraction numerator g r a m space A g subscript 2 C r O subscript 4 end subscript over denominator M r end fraction  2 x 10 to the power of negative 2 end exponent m o l equals fraction numerator g r a m space A g subscript 2 C r O subscript 4 end subscript over denominator 332 end fraction  g r a m space A g subscript 2 C r O subscript 4 equals 2 cross times 10 to the power of negative 2 end exponent m o l space cross times space 332 equals 6 comma 64 g r a m

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