Pertanyaan

$Laru\tan\;HC\mathcal l\;0,8\;M\;sebanyak\;100\;mL\;ditambahkan\;pada\;100\;mL\;laru\tan\;NH_3\;0,8\;M\;(Kb\;NH_3\;=\;1\;x\;10^{-5},\;Kw\;=10^{-14})\;menurut\;reaksi:\;\\NH_3\;(aq)\;+\;HC\mathcal l\;(aq)\;\textemdash)\;NH_4C\mathcal l\;(aq)\;\\Harga\;pH\;laru\tan\;yang\;terjadi\;adalah....\\$

5 — log 2
5 +log 2
5 +log 4
9 — log 4
9 +log 2

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D. Ayu

Master Teacher

Mahasiswa/Alumni Universitas Negeri Jakarta

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Pembahasan

$N H subscript 3 left parenthesis a q right parenthesis plus H C l left parenthesis a q right parenthesis rightwards arrow N H subscript 4 C l left parenthesis a q right parenthesis 0 comma 8 M space space space space space space space space space space 0 comma 8 M 100 m L space space space space space space space 100 m L D i t a n y a space colon space h a r g a space p H space l a r u t a n space y a n g space t e r j a d i ? space space space space space space space space N H subscript 3 left parenthesis a q right parenthesis space space space space space space space space space space space space space space space space space plus space space space space space space space space space space space space space H C I left parenthesis a q right parenthesis rightwards arrow N H subscript 4 C l left parenthesis a q right parenthesis space space space space space space space space space space 0 comma 8 M x 100 m L space space space space space space space space space space space space space space space space 0 comma 8 M x 100 m L M equals 80 m m o l space space space space space space space space space space space space space space space space space space space space space space space space space space space equals 80 m m o l space space space space space space space space space space space space space space space minus bottom enclose R equals 80 m m o l space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space 80 m m o l space space space space space space space space space 80 m m o l end enclose S equals negative space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space minus space space space space space space space space space space space space space space space space space space 80 m m o l M o l a r i t a s g a r a m equals fraction numerator m m o l space g a r a m over denominator v o l u m e space t o t a l end fraction equals fraction numerator 80 m m o l over denominator 200 m L end fraction equals 0 comma 4 M K a r e n a space s e m u a space r e a k t a n space h a b i s comma space b e r a r t i space m e r u p a k a n space c a m p u r a n space h i d r o l i s i s. space H i d r o l i s i s space d i l i h a t space d a r i space s i f a t space y a n g space k u a t comma space d i s i n i space y a n g space k u a t space a d a l a h space H C l space left parenthesis a s a m right parenthesis. R u m u s space H i d r o l i s i s space u n t u k space G a r a m space a s a m colon left square bracket H to the power of plus right square bracket equals square root of fraction numerator K w space x space M o l a r i t a s space G a r a m space x space v a l e n s i over denominator K b end fraction end root left square bracket H to the power of plus right square bracket equals square root of fraction numerator 10 to the power of negative 14 end exponent space cross times 0 comma 4 M space cross times space 1 over denominator 10 to the power of negative 5 end exponent end fraction end root left square bracket H to the power of plus right square bracket equals square root of 4 cross times 10 to the power of negative 10 end exponent end root left square bracket H to the power of plus right square bracket equals 2 cross times 10 to the power of negative 5 end exponent p H equals negative l o g left square bracket H to the power of plus right square bracket equals negative l o g left square bracket 2 cross times 10 to the power of negative 5 end exponent right square bracket equals 5 minus l o g 2$

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