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Pertanyaan

P a d a space r u a n g a n space 1 space l i t e r space d i p a n a s k a n space 1 space m o l space g a s space N subscript 2 O subscript 4 space end subscript t e r j a d i space r e a k s i space N subscript 2 O subscript 4 space end subscript space left parenthesis g right parenthesis space leftwards arrow over rightwards arrow space 2 space space N O subscript 2 space end subscript space left parenthesis g right parenthesis  D a t a space y a n g space d i p e r o l e h colon

H a r g a space K c space p a d a space r e a k s i space t e r s e b u t space a d a l a h..

  1. K c space equals space fraction numerator open parentheses 0 comma 4 close parentheses squared over denominator open parentheses 0 comma 2 close parentheses end fraction

  2. K c space equals space fraction numerator open parentheses 0 comma 4 close parentheses squared over denominator open parentheses 0 comma 8 close parentheses end fraction

  3. K c space equals space fraction numerator open parentheses 0 comma 8 close parentheses over denominator open parentheses 0 comma 4 close parentheses squared end fraction

  4. K c space equals space fraction numerator open parentheses 0 comma 8 close parentheses over denominator open parentheses 0 comma 2 close parentheses end fraction

  5. K c space equals space fraction numerator open parentheses 0 comma 4 close parentheses over denominator open parentheses 0 comma 2 close parentheses end fraction

M. Robo

Master Teacher

Jawaban terverifikasi

Pembahasan

H a r g a space K c space d i h i t u n g space p a d a space s a a t space k e a d a a n space s e t i m b a n g. space  K c space equals space fraction numerator left square bracket N O subscript 2 right square bracket squared over denominator left square bracket N subscript 2 O subscript 4 right square bracket end fraction equals fraction numerator left square bracket 0 comma 4 right square bracket squared over denominator left square bracket 0 comma 8 right square bracket end fraction

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