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Ke d a l am 100 m L l a r u tan C H 3 ​ COO H 0 , 2 M ( K a = 1 x 1 0 − 5 ) d i t ambahkan 100 m L l a r u tan N a O H 0 , 2 M se hin gg a t er ja d i re ak s i : C H 3 ​ COO H ( a q ) + N a O H ( a q ) → C H 3 ​ COON a ( a q ) + H 2 ​ O ( l ) H a r g a p H l a r u tan y an g t er ja d i se b es a r .. ( K w = 1 0 − 14 )

  1. 5

  2. 6

  3. 9

  4. 10

  5. 11

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M. Robo

Master Teacher

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space space space space space space space space space space space space space space space space space space space C H subscript 3 C O O H space space plus space space space space N a O H space space space space rightwards arrow space C H subscript 3 C O O N a space space plus space H subscript 2 O space  M u l a space space space space space space space space space space space space space 20 space m m o l space space space space space space space space 20 space m m o l  R e a k s i space space space space space space space minus 20 space m m o l space space space minus 20 space m m o l space space space space space space space space plus 20 space m m o l space space space space space plus 20 space m m o l  S i s a space space space space space space space space space space space space space space space space 0 space space space space space space space space space space space space space space space space space space space space space space 0 space space space space space space space space space space space space space space space space space space space space space space 20 space m m o l space space space space space space space space space space 20 space m m o l    left square bracket C H subscript 3 C O O N a right square bracket space equals space fraction numerator m o l over denominator V t o t a l end fraction space equals space fraction numerator 0 comma 02 space m o l over denominator 0 comma 2 space L end fraction space equals space 0 comma 1 space M  C H subscript 3 C O O N a space m e r u p a k a n space g a r a m space b a s a comma space s e h i n g g a colon  left square bracket O H to the power of minus right square bracket space equals space square root of fraction numerator K w space x space left square bracket g a r a m right square bracket over denominator K a end fraction end root space equals space square root of fraction numerator 10 to the power of negative 14 end exponent space x space left square bracket 0 comma 1 right square bracket over denominator 10 to the power of negative 5 end exponent end fraction end root space equals space square root of 10 to the power of negative 10 end exponent end root space equals space 10 to the power of negative 5 end exponent space M  p O H space equals space minus space log space 10 to the power of negative 5 end exponent space equals space 5  p H space equals space 14 space minus space p O H  space space space space space space equals space 14 space minus space 5  p H space equals space 9

Latihan Bab

Konsep Kilat

Pendahuluan Hidrolisis Garam

Hidrolisis Parsial Garam Asam

Hidrolisis Parsial Garam Basa

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Pertanyaan serupa

Hitunglah pH larutan CH 3 ​ COONa 0,008 M sebanyak 100 mL. Jika K a ​ CH 3 ​ COOH = 2 × 1 0 − 5 .

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