Pertanyaan

S e ban y ak 172 g r am k r i s t a l ka l s i u m s u l f a t C a S O 4 . x H 2 O d i p ana s kan se hin gg a t er b e n t u k 136 g r am k r i s t a l C a S O 4 m e n u r u t re ak s i : C a S O 4 . x H 2 0 ( s ) → C a S O 4 ( s ) + x H 2 O ( g ) . R u m u s se n y a w a d a l am k r i s t a l ka l s i u m s u l f a t t erse b u t a d a l ah ... ( A r C a = 40 ; S = 32 ; O = 16 ; H = 1 )

$S e ban y ak 172 g r am k r i s t a l ka l s i u m s u l f a t C a S O_{4} . x H_{2} O d i p ana s kan se hin gg a t er b e n t u k 136 g r am k r i s t a l C a S O_{4} m e n u r u t re ak s i : C a S O_{4} . x H_{2} 0 (s) \to C a S O_{4} (s) + x H_{2} O (g) . R u m u s se n y a w a d a l am k r i s t a l ka l s i u m s u l f a t t erse b u t a d a l ah ... (A r C a = 40; S = 32; O = 16; H = 1)$

A. Ratna

Master Teacher

Mahasiswa/Alumni Universitas Negeri Malang

Jawaban terverifikasi

Pembahasan

$M a s s a space h i d r a t space left parenthesis C a S O subscript 4. x H subscript 2 O right parenthesis space a d a l a h space 172 space g r a m comma space k e t i k a space d i p a n a s k a n space a d a space m a s s a space h i l a n g comma space m a s s a space y a n g space h i l a n g space i n i space m e r u p a k a n space m a s s a space H subscript 2 O. space K e m u d i a n space m a s s a space t e r s i s a space a d a l a h space 136 space g r a m space i n i space m e r u p a k a n space m a s s a space a n h i d r a t space left parenthesis g a r a m space m u r n i right parenthesis. space M a s s a space H subscript 2 O space space equals space m a s s a space h i d r a t space – space m a s s a space a n h i d r a t space space space space space space space space space space space space space space space space space space space space space space space space equals space 172 space g r a m space – space 136 space g r a m space space space space space space space space space space space space space space space space space space space space space space space equals space 36 space g r a m K e m u d i a n comma space u n t u k space m e n e n t u k a n space j u m l a h space H 2 O space m a k a space h i t u n g space p e r b a n d i n g a n space m o l space d a r i space H subscript 2 O space d a n space g a r a m. space m o l space C a S O subscript 4 space colon space M o l space H subscript 2 O space equals space fraction numerator m a s s a space C a S O subscript 4 over denominator M r space C a S O subscript 4 end fraction space colon space fraction numerator m a s s a space H subscript 2 O over denominator M r space H subscript 2 O end fraction space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space equals 136 over 136 space colon space 36 over 18 space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space equals 1 space colon space 2$

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