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x → ∞ lim ​ x 2 − 3 x − 4 ​ − x − 1

   

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A. Salim

Master Teacher

Mahasiswa/Alumni Universitas Pelita Harapan

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Jawaban

nilai adalah .

nilai undefined adalah begin mathsize 14px style negative 5 over 2 end style.

Pembahasan

Menyelesaikan limit dengan cara berikut. Untuk , diperoleh Jadi, nilai adalah .

Menyelesaikan limit dengan cara berikut.

begin mathsize 14px style limit as x rightwards arrow infinity of square root of a x squared plus b c plus c end root minus square root of p x squared plus q x plus r end root equals open curly brackets table attributes columnalign left end attributes row cell plus infinity space text untuk end text space a greater than p end cell row cell negative infinity text  untuk end text space a less than p end cell row cell fraction numerator b minus q over denominator 2 square root of a end fraction space text untuk end text space a equals p end cell end table close end style 

Untuk begin mathsize 14px style limit as x rightwards arrow infinity of square root of x squared minus 3 x minus 4 end root minus x minus 1 end style, diperoleh

begin mathsize 12px style table attributes columnalign right center left columnspacing 0px end attributes row cell limit as x rightwards arrow infinity of square root of x squared minus 3 x minus 4 end root minus x minus 1 end cell equals cell limit as x rightwards arrow infinity of square root of x squared minus 3 x minus 4 end root minus square root of open parentheses x plus 1 close parentheses squared end root end cell row blank equals cell limit as x rightwards arrow infinity of square root of x squared minus 3 x minus 4 end root minus square root of x squared plus 2 x plus 1 end root end cell row blank equals cell fraction numerator negative 3 minus 2 over denominator 2 square root of 1 end fraction end cell row blank equals cell negative 5 over 2 end cell end table end style  

Jadi, nilai undefined adalah begin mathsize 14px style negative 5 over 2 end style.

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